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  • poj 1987 节点距离小于等于K(树DP)

    这题和poj 1741是一模一样的

    但是1741能AC的代码,在这里却是TLE,暂时没看出哪里出现了问题。。

    AC代码:

    #include <iostream>
    #include <string>
    #include <cstring>
    #include <cstdlib>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    #include <stack>
    #include <queue>
    #include <cctype>
    #include <vector>
    #include <iterator>
    #include <set>
    #include <map>
    #include <sstream>
    using namespace std;
    
    #define mem(a,b) memset(a,b,sizeof(a))
    #define pf printf
    #define sf scanf
    #define spf sprintf
    #define pb push_back
    #define debug printf("!
    ")
    #define MAXN 40000+5
    #define MAX(a,b) a>b?a:b
    #define blank pf("
    ")
    #define LL long long
    #define ALL(x) x.begin(),x.end()
    #define INS(x) inserter(x,x.begin())
    #define pqueue priority_queue
    #define INF 0x3f3f3f3f
    
    #define ls (rt<<1)
    #define rs (rt<<1|1)
    
    int n,m,k;
    
    int ans,root,tot,ptr = 1,K,son[MAXN],head[MAXN],f[MAXN],dist[MAXN],d[MAXN],sum,vis[MAXN];
    
    struct node{int y,next,v;}tree[MAXN<<2];
    
    void add(int u,int v,int w) {tree[ptr].y=v;tree[ptr].v=w;tree[ptr].next=head[u];head[u]=ptr++;}
    
    void getroot(int x,int fa)
    {
        son[x] = 1;
        f[x] = 0;
        for(int i=head[x];i!=-1;i=tree[i].next)
        {
            int y = tree[i].y;
            if(y == fa || vis[y]) continue;
            getroot(y,x);
            son[x] += son[y];
            f[x] = max(f[x] , son[y]);
        }
        f[x] = max(f[x] , sum - son[x]);
        if(f[x] < f[root]) root = x;
    }
    
    void getdis(int x,int fa)
    {
        if(d[x] <= K) dist[tot++]=d[x];
        for(int i=head[x];i!=-1;i=tree[i].next)
        {
            int y = tree[i].y;
            if(y == fa || vis[y]) continue;
            d[y] = d[x] + tree[i].v;
            getdis(y,x);
        }
    }
    
    int cal(int x,int now)
    {
        d[x]=now;
        tot = 0;
        getdis(x,0);
        sort(dist,dist+tot);
        int all = 0,left=0,right = tot-1;
        while(left<right)
        {
            if(dist[left]+dist[right] <= K) {all+=right-left;left++;}
            else right--;
        }
        return all;
    }
    void solve(int x)
    {
        ans+=cal(x,0);
        vis[x] = 1;
        for(int i=head[x];i!=-1;i=tree[i].next)
        {
            int y = tree[i].y;
            if(vis[y]) continue;
            ans-=cal(y,tree[i].v);
            sum = son[y];
            root = 0;
            getroot(y,root);
            solve(root);
        }
    }
    void init()
    {
        mem(head,-1);
        ptr = 1;
        ans = root = 0;
        mem(vis,0);
        sum=n;
        f[0]=INF;
    }
    
    int main()
    {
        while(~sf("%d%d",&n,&m))
        {
            init();
            for(int i=1;i<n;i++)
            {
                int x,y,z;char ch[2];
                sf("%d%d%d%s",&x,&y,&z,ch);
                add(x,y,z);
                add(y,x,z);
            }
            sf("%d",&K);
            getroot(1,0);
            solve(root);
            pf("%d
    ",ans);
        }
    
    }

    1741可AC,这题TLE

    #include <iostream>
    #include <string>
    #include <cstring>
    #include <cstdlib>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    #include <stack>
    #include <queue>
    #include <cctype>
    #include <vector>
    #include <iterator>
    #include <set>
    #include <map>
    #include <sstream>
    using namespace std;
    
    #define mem(a,b) memset(a,b,sizeof(a))
    #define pf printf
    #define sf scanf
    #define spf sprintf
    #define pb push_back
    #define debug printf("!
    ")
    #define MAXN 40000+5
    #define MAX(a,b) a>b?a:b
    #define blank pf("
    ")
    #define LL long long
    #define ALL(x) x.begin(),x.end()
    #define INS(x) inserter(x,x.begin())
    #define pqueue priority_queue
    #define INF 0x3f3f3f3f
    
    #define ls (rt<<1)
    #define rs (rt<<1|1)
    
    int n,m,k;
    
    int ptr = 1,head[MAXN],vis[MAXN],f[MAXN],d[MAXN];
    
    int ans,tot,rt,sum,son[MAXN],dis[MAXN],mu[MAXN];
    
    struct node
    {
        int y,val,next;
    }tree[MAXN<<2];
    
    void init()
    {
        mem(tree,0);
        mem(head,-1);
        mem(vis,0);
        mem(dis,0);
        ans = 0;
        ptr = 1;
        sum = n;
        f[0] = INF;
    }
    
    void add(int fa,int son,int val)
    {
        tree[ptr].y = son;
        tree[ptr].val = val;
        tree[ptr].next = head[fa];
        head[fa] = ptr++;
    }
    
    void getroot(int root,int fa)
    {
        son[root] = 1;
        f[root] = 0;
        for(int i=head[root];i!=-1;i=tree[i].next)
        {
            int y = tree[i].y;
            if(vis[y] || y == fa) continue;
            getroot(y,root);
            son[root] += son[y];
            f[root] = max(son[y],f[root]);
        }
        f[root] = max(f[root],sum-son[root]);
        if(f[root]<f[rt]) rt = root;
    }
    
    void getdis(int root,int fa)
    {
        if(d[root]<=k) dis[tot++] = d[root];
        for(int i=head[root];i!=-1;i=tree[i].next)
        {
            int y = tree[i].y;
            if(vis[y] || y == fa) continue;
            d[y] = d[root] + tree[i].val;
            getdis(y,root);
        }
    }
    
    int getcnt(int root,int now)
    {
        d[root] = now;
        tot = 0;
        getdis(root,0);
        sort(dis,dis+tot);
        int left =0,right = tot-1,ans=0;
        while(left<right)
        {
            if(dis[left]+dis[right]<=k)
            {
                ans+= right-left;
                left++;
            }
            else right--;
        }
        return ans;
    }
    
    void solve(int root)
    {
        //pf("rt%d
    ",rt);
        ans+=getcnt(root,0);
        vis[root] = 1;
        for(int i=head[root];i!=-1;i=tree[i].next)
        {
            int y = tree[i].y;
            if(vis[y]) continue;
            ans-=getcnt(y,tree[i].val);
            sum = son[y];
            rt = 0;
            getroot(y,rt);
            solve(rt);
        }
    }
    
    
    int main()
    {
        int i,j,t,kase=1;
        while(~sf("%d%d",&n,&m),n+m)
        {
            init();
            int x,y,z;
            char ch[2];
            for(i=1;i<n;i++)
            {
                sf("%d%d%d%s",&x,&y,&z,ch);
                add(x,y,z);
                add(y,x,z);
            }
            sf("%d",&k);
            getroot(1,0);
            solve(rt);
            pf("%d
    ",ans);
        }
        return 0;
    }

    以及:http://blog.csdn.net/woshi250hua/article/details/7723400

    我看起来是一样的,就是不知道TLE的原因。。

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  • 原文地址:https://www.cnblogs.com/qlky/p/5784860.html
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