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  • hdu 2544 最短路 (dijkstra,floyd)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2544

    题目大意:找到两点间最短的距离值。

    代码一:(dijkstra算法)

     1 #include <iostream>
     2 #include <cstdio>
     3 using namespace std;
     4 int n,Min,node[105],visit[105],map[105][105];
     5 void set()
     6 {
     7     for (int i=1; i<=n; i++)
     8     {
     9         node[i]=999999;
    10         visit[i]=0;
    11         for (int j=1; j<=n; j++)
    12             map[i][j]=999999;
    13     }
    14 }
    15 int dijkstra(int m)
    16 {
    17     int tm=m;
    18     visit[m]=1;
    19     node[m]=0;
    20     for (int k=2; k<=n; k++)
    21     {
    22         Min=999999;
    23         for (int i=1; i<=n; i++)
    24             if (!visit[i])
    25             {
    26                 if (node[i]>map[tm][i]+node[tm])
    27                     node[i]=map[tm][i]+node[tm];
    28                 if (Min>node[i])
    29                 {
    30                     Min=node[i];
    31                     m=i;
    32                 }
    33             }
    34         visit[m]=1;
    35         tm=m;
    36     }
    37     return node[1];
    38 }
    39 int main ()
    40 {
    41     int m,a,b,c;
    42     while (scanf("%d%d",&n,&m),(n||m))
    43     {
    44         set();
    45         while (m--)
    46         {
    47             scanf("%d%d%d",&a,&b,&c);
    48             if (c<map[a][b])
    49             map[a][b]=map[b][a]=c;
    50         }
    51         printf("%d
    ",dijkstra(n));
    52     }
    53 }

    代码二:(floyd算法)

     1 #include <iostream>
     2 #include <cstdio>
     3 using namespace std;
     4 int map[205][205];
     5 const int INF=9999999;
     6 
     7 int main ()
     8 {
     9     int n,m;
    10     while(~scanf("%d%d",&n,&m))
    11     {
    12         if (n==0&&m==0)
    13             break;
    14         for (int i=1; i<=n; i++)
    15             for (int j=1; j<=n; j++)
    16             {
    17                 if (i!=j)
    18                     map[i][j]=map[j][i]=INF;
    19                 else
    20                     map[i][j]=map[j][i]=0;
    21             }
    22         while (m--)
    23         {
    24             int a,b,c;
    25             scanf("%d%d%d",&a,&b,&c);
    26             if (map[a][b]>c)
    27                 map[a][b]=map[b][a]=c;
    28         }
    29         for (int k=1; k<=n; k++)
    30             for (int i=1; i<=n; i++)
    31                 for (int j=1; j<=n; j++)
    32                     if (map[i][j]>map[i][k]+map[k][j])
    33                         map[i][j]=map[j][i]=map[i][k]+map[k][j];
    34         printf ("%d
    ",map[1][n]);
    35 
    36     }
    37     return 0;
    38 }
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  • 原文地址:https://www.cnblogs.com/qq-star/p/3907024.html
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