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  • C语言上机练习二

    1 //1001
    2 #include<stdio.h>
    3 int main()
    4 {
    5     int a,b;
    6     while(~scanf("%d%d",&a,&b))
    7         printf("%d
    ",a+b);
    8 }
     1 //1002
     2 #include<stdio.h>
     3 #include<string.h>
     4 char s[1000];
     5 int main()
     6 {
     7     int i,t,d,x,m;
     8     while(gets(s)!=NULL)
     9     {
    10         t=strlen(s);
    11         for(i=d=x=m=0; i<t; ++i)
    12         {
    13             if(s[i]>='A'&&s[i]<='Z')
    14                 d++;
    15             if(s[i]>='a'&&s[i]<='z')
    16                 x++;
    17             if(s[i]>='0'&&s[i]<='9')
    18                 m++;
    19         }
    20         printf("%d %d %d
    ",d,x,m);
    21     }
    22 }
     1 //1003
     2 #include<stdio.h>
     3 int main()
     4 {
     5     int a,b,r,t,x,y;
     6     while(~scanf("%d%d",&a,&b))
     7     {
     8         x=a;
     9         y=b;
    10         if(a<b)
    11         {
    12             t=a;
    13             a=b;
    14             b=t;
    15         }
    16         do
    17         {
    18             r=a%b;
    19             a=b;
    20             b=r;
    21         }while(r);
    22         x/=a;
    23         y/=a;
    24         printf("%d %d
    ",a,x*y*a);
    25     }
    26 }
     1 //1004
     2 #include<stdio.h>
     3 int main()
     4 {
     5     int i,s,n;
     6     while(~scanf("%d",&n))
     7     {
     8         for(i=s=1; i<=n; ++i)
     9             s*=i;
    10         printf("%d
    ",s);
    11     }
    12 }
     1 //1005
     2 #include<stdio.h>
     3 #include<string.h>
     4 int a[10000];
     5 int main()
     6 {
     7     int n,i,j,len=0;
     8     while(~scanf("%d",&n))
     9     {
    10         memset(a,0,sizeof a);
    11         for(i=2,a[0]=1,len=1; i<=n; ++i)
    12         {
    13             for(j=0; j<=len; ++j)
    14             {
    15                 if(j)
    16                 {
    17                     a[j]=a[j]*i+a[j-1]/10000;
    18                     a[j-1]%=10000;
    19                 }
    20                 else
    21                     a[j]*=i;
    22             }
    23             if(a[len])
    24                 len++;
    25             
    26         }
    27         for(i=len-1; i>=0; --i)
    28             if(i==len-1)
    29                 printf("%d",a[i]);
    30             else
    31                 printf("%04d",a[i]);
    32         printf("
    ");
    33     }
    34 }
     1 //1006
     2 #include<stdio.h>
     3 int a[100000];
     4 int main()
     5 {
     6     int i,n;
     7     while(~scanf("%d",&n))
     8     {
     9         for(i=0; i<n; ++i)
    10             scanf("%d",&a[i]);
    11         for(i=n-1; i>=0; --i)
    12             if(i)
    13                 printf("%d ",a[i]);
    14             else
    15                 printf("%d",a[i]);
    16         printf("
    ");
    17     }
    18 }
     1 //1007
     2 #include<stdio.h>
     3 int a[100000];
     4 int main()
     5 {
     6     int i,j,s,n;
     7     while(~scanf("%d",&n))
     8     {
     9 
    10         for(j=0,i=1; i<n; ++i)
    11             if(!(n%i))
    12                 a[j++]=i;
    13         for(i=s=0; i<j; ++i)
    14             s+=a[i];
    15         if(s==n)
    16         {
    17             printf("Yes
    ");
    18             for(i=0; i<j; ++i)
    19                 if(i)
    20                     printf(" %d",a[i]);
    21                 else
    22                     printf("%d",a[i]);
    23             printf("
    ");
    24         }
    25         else
    26             printf("No
    ");
    27     }
    28 }
     1 //1008
     2 #include<stdio.h>
     3 int a[100000];
     4 int main()
     5 {
     6     int i,j,s,t,n;
     7     while(~scanf("%d",&n))
     8     {
     9         for(i=0; i<n; ++i)
    10             scanf("%d",&a[i]);
    11         for(i=0; i<n-1; ++i)
    12             for(j=0; j<n-1-i; ++j)
    13                 if(a[j]>a[j+1])
    14                 {
    15                     t=a[j];
    16                     a[j]=a[j+1];
    17                     a[j+1]=t;
    18                 }
    19         for(i=0; i<n; ++i)
    20             if(i)
    21                 printf(" %d",a[i]);
    22             else
    23                 printf("%d",a[i]);
    24         printf("
    ");
    25     }
    26 }
     1 #include<stdio.h>
     2 #include<string.h>
     3 int a[10][10];
     4 int main()
     5 {
     6     int n,x,y,t;
     7     while(~scanf("%d",&n))
     8     {
     9         memset(a,0,sizeof a);
    10         t=a[x=0][y=n-1]=n*n;
    11         while(t>1)
    12         {
    13             while(x+1<n&&!a[x+1][y])  a[++x][y]=--t;
    14             while(y-1>=0&&!a[x][y-1]) a[x][--y]=--t;
    15             while(x-1>=0&&!a[x-1][y]) a[--x][y]=--t;
    16             while(y+1<n&&!a[x][y+1])  a[x][++y]=--t;
    17         }
    18         for(x=0; x<n; ++x)
    19         {
    20             for(y=0; y<n; ++y)
    21                 if(y)
    22                     printf(" %d",a[x][y]);
    23                 else
    24                     printf("%d",a[x][y]);
    25             printf("
    ");
    26         }
    27     }
    28 }
     1 //1010(百度康托展开,可以得到你想要的)
     2 #include<stdio.h>
     3 #include<string.h>
     4 char s[8];
     5 int a[8]={5040,720,120,24,6,2,1};
     6 int main()
     7 {
     8     int n,len,i,j,sum,t;
     9     while(~scanf("%d",&n))
    10     {
    11         getchar();
    12         while(n--)
    13         {
    14             gets(s);
    15             len=strlen(s);
    16             for(i=sum=0; i<len; ++i)
    17             {
    18                 for(j=i+1,t=0; j<len; ++j)
    19                     if(s[j]<s[i])
    20                         ++t;
    21                 sum+=t*a[i];
    22             }
    23             printf("%d
    ",++sum);
    24         }
    25     }
    26 }
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  • 原文地址:https://www.cnblogs.com/qq188380780/p/6055985.html
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