zoukankan      html  css  js  c++  java
  • ZOJ 2975 Kinds of Fuwas

    K - Kinds of Fuwas
    Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu

    Description

    In the year 2008, the 29th Olympic Games will be held in Beijing. This will signify the prosperity of China as well as becoming a festival for people all over the world.

    The official mascots of Beijing 2008 Olympic Games are Fuwa, which are named as Beibei, Jingjing, Haunhuan, Yingying and Nini. Fuwa embodies the natural characteristics of the four most popular animals in China -- Fish, Panda, Tibetan Antelope, Swallow -- and the Olympic Flame. To popularize the official mascots of Beijing 2008 Olympic Games, some volunteers make a PC game with Fuwa.

    As shown in the picture, the game has a matrix of Fuwa. The player is to find out all the rectangles whose four corners have the same kind of Fuwa. You should make a program to help the player calculate how many such rectangles exist in the Fuwa matrix.

    Input

    Standard input will contain multiple test cases. The first line of the input is a single integer T (1 <= T <= 50) which is the number of test cases. And it will be followed by T consecutive test cases.

    The first line of each test case has two integers M and N (1 <= M, N <= 250), which means the number of rows and columns of the Fuwa matrix. And then there are M lines, each has N characters, denote the matrix. The characters -- 'B' 'J' 'H' 'Y' 'N' -- each denotes one kind of Fuwa.

    Output

    Results should be directed to standard output. The output of each test case should be a single integer in one line, which is the number of the rectangles whose four corners have the same kind of Fuwa.

    Sample Input

    2
    2 2
    BB
    BB
    5 6
    BJHYNB
    BHBYYH
    BNBYNN
    JNBYNN
    BHBYYH
    

    Sample Output

    1
    8
     1 #include<iostream>  
     2 #include<string.h>  
     3 #include<stdio.h>  
     4 #include<ctype.h>  
     5 #include<algorithm>  
     6 #include<stack>  
     7 #include<queue>  
     8 #include<set>  
     9 #include<math.h>  
    10 #include<vector>  
    11 #include<map>  
    12 #include<deque>  
    13 #include<list>  
    14 using namespace std;    
    15 int main()  
    16 {  
    17     int a;  
    18     cin>>a;  
    19     while(a--)  
    20     {  
    21         
    22         int n,m,t;  
    23         cin>>n>>m;
    24         char JU[260][260];//输入信息  
    25         for(int i=0;i<n;i++)  
    26         for(int j=0;j<m;j++)  
    27         cin>>JU[i][j]; 
    28         char wa[]={"BJHYN"};
    29         int he=0    ;
    30         for(int i=0;i<n;i++)  
    31         for(int j=i+1;j<n;j++)  
    32         {  
    33             for(int p=0;p<5;p++)  
    34             {  
    35                 t=0;  
    36                 for(int l=0;l<m;l++)  
    37                 if(JU[i][l]==wa[p]&&JU[j][l]==wa[p])//划线……  
    38                 t=t+1;  
    39                 he=he+t*(t-1)/2;//等差数列求和  
    40             }  
    41         }  
    42         printf("%d
    ",he);  
    43     }  
    44     return 0;  
    45 }  
    View Code

  • 相关阅读:
    【习题 3-12 UVA
    【习题 3-9 UVA
    【Codeforces Round #299 (Div. 2) E】Tavas and Pashmaks
    分布式ID生成器的解决方案总结
    Spring MVC表单防重复提交
    Spring import配置文件使用占位符
    什么是灰度发布,灰度测试。
    浅析负载均衡的6种算法,Ngnix的5种算法。
    神器,阿里巴巴Java代码检查插件
    去BAT面试完的Mysql面试题总结(55道,带完整答案)
  • 原文地址:https://www.cnblogs.com/qscqesze/p/3851769.html
Copyright © 2011-2022 走看看