Educational Codeforces Round 2 B. Queries about less or equal elements 水题

B. Queries about less or equal elements

Time Limit: 20 Sec

Memory Limit: 256 MB

题目连接

http://codeforces.com/contest/600/problem/B

Description

You are given two arrays of integers a and b. For each element of the second array bj you should find the number of elements in array athat are less than or equal to the value bj.

Input

The first line contains two integers n, m (1 ≤ n, m ≤ 2·105) — the sizes of arrays a and b.

The second line contains n integers — the elements of array a ( - 109 ≤ ai ≤ 109).

The third line contains m integers — the elements of array b ( - 109 ≤ bj ≤ 109).

Output

Print m integers, separated by spaces: the j-th of which is equal to the number of such elements in array a that are less than or equal to the value bj.

Sample Input

5 4
1 3 5 7 9
6 4 2 8

Sample Output

3 2 1 4

HINT

题意

给你一个数组，然后有Q次询问，问你在数组中，有多少个数比他小

题解：

把数组扔进一个vector里面，排序，然后二分就好了~

代码：

#include<iostream>
#include<stdio.h>
#include<algorithm>
using namespace std;
#define maxn 200005
int a[maxn];
int b[maxn];
vector<int> Q;
int main()
{
    int n,m;
    scanf("%d%d",&n,&m);
    for(int i=1;i<=n;i++)
    {
        scanf("%d",&a[i]);
        Q.push_back(a[i]);
    }
    sort(Q.begin(),Q.end());
    for(int i=1;i<=m;i++)
    {
        int p;scanf("%d",&p);
        int x = upper_bound(Q.begin(),Q.end(),p)-Q.begin();
        printf("%d
",x);
    }
}