Codeforces Beta Round #7 C. Line Exgcd

C. Line

题目连接：

http://www.codeforces.com/contest/7/problem/C

Description

A line on the plane is described by an equation Ax + By + C = 0. You are to find any point on this line, whose coordinates are integer numbers from  - 5·1018 to 5·1018 inclusive, or to find out that such points do not exist.

Input

The first line contains three integers A, B and C ( - 2·109 ≤ A, B, C ≤ 2·109) — corresponding coefficients of the line equation. It is guaranteed that A2 + B2 > 0.

Output

Output the sequence of lines. Each line should contain either the result of alloc operation procession , or ILLEGAL_ERASE_ARGUMENT as a result of failed erase operation procession. Output lines should go in the same order in which the operations are processed. Successful procession of alloc operation should return integers, starting with 1, as the identifiers of the allocated blocks.

Sample Input

2 5 3

Sample Output

6 -3

Hint

题意

给你一条直线，让你找出直线上的一个整数点，不存在输出-1

题解：

exgcd裸题

求一下ax+by=gcd(a,b)的x,y之后，再check一下-c%gcd(a,b)是否等于0就好了，不等于0，那就输出-1

否则就怼一波。

代码

#include<bits/stdc++.h>
using namespace std;

void gcd(long long a,long long b,long long& d,long long& x,long long& y)
{
    if(!b){d=a,x=1,y=0;}
    else{gcd(b,a%b,d,y,x);y-=x*(a/b);}
}
int main()
{
    long long a,b,c,d,x,y;
    cin>>a>>b>>c;c=-c;
    gcd(a,b,d,x,y);
    if(c%d!=0)return puts("-1"),0;
    else
    {
        printf("%lld %lld
",x*c/d,y*c/d);
    }
}