zoukankan      html  css  js  c++  java
  • kuangbin_MST A (POJ 1251)

    模板题 Kruskal直接过 调试时候居然在sort(edge + 1, edge + 1 + m)上浪费好多时间...

    不过本着ACMer的心态自然要测试一下两种方法分别的速度

    Kruskal : Memory 392 Time 16

    Prim: Memory 576 Time 16

    ...........哦居然一样啊

    Prim

    #include <cstdio>
    #include <cstring>
    #include <queue>
    #include <vector>
    #include <algorithm>
    #define INF 0x3F3F3F3F
    using namespace std;
    
    typedef pair<int, int> pii;
    struct cmp{
        bool operator() (const pii a, const pii b){
            return a.first > b.first;
        }
    };
    
    int size, head[30], point[200], nxt[200], val[200];
    int n, dist[30];
    
    void init()
    {
        size = 0;
        memset(head, -1 ,sizeof head);
    }
    
    void add(int from, int to, int value)
    {
        val[size] = value;
        point[size] = to;
        nxt[size] = head[from];
        head[from] = size++;
    }
    
    int prim(int s)
    {
        int ans = 0;
        bool vis[30];
        memset(dist, 0x3f, sizeof dist);
        memset(vis, false, sizeof vis);
        
        priority_queue<pii, vector<pii>, cmp> q;
        for(int i = head[s]; ~i; i = nxt[i]){
            dist[point[i]] = val[i];
            q.push(make_pair(val[i], point[i]));
        }
        dist[s] = 0;
        vis[s] = true;
        while(!q.empty()){
            pii u = q.top();
            q.pop();
            if(vis[u.second]) continue;
            vis[u.second] = true; 
            ans += u.first;
            for(int i = head[u.second]; ~i; i = nxt[i]){
                int j = point[i];
                //printf("check edge[%d][%d] vis = %d value = %d
    ", u.second, j, vis[j], val[i]);
                if(!vis[j] && dist[j] > val[i]){
                    //printf("add edge[%d][%d]
    ", u.second, j);
                    dist[j] = val[i];
                    q.push(make_pair(dist[j], j));
                }
            }
        }
        return ans;
    }
    
    int main()
    {
        while(scanf("%d", &n), n){
            init();
            for(int i = 1; i < n; i++){
                int k;
                scanf("%*s%d", &k);
                while(k--){
                    char to[2];
                    int value;
                    scanf("%s%d", to, &value);
                    add(i, to[0]-'A'+1, value);
                    add(to[0]-'A'+1, i, value);
                }
            }
            printf("%d
    ", prim(1));
        }            
        return 0;
    }

    Kruskal

    #include <cstdio>
    #include <cstring>
    #include <queue>
    #include <vector>
    #include <algorithm>
    #define INF 0x3F3F3F3F
    using namespace std;
    
    int n, m;
    int parent[100], rank[100];
    struct Edge{int u, v, w;}edge[100];
    
    bool cmp(Edge a, Edge b)
    {
        return a.w < b.w;
    }
    
    inline int FindSet(int x)
    {
        while(x != parent[x]) x = parent[x];
        return x;
    }
    
    void UnionSet(int l, int r)
    {
        int x = FindSet(l);
        int y = FindSet(r);
        if(rank[x] > rank[y]){
            rank[x] += rank[y];
            parent[y] = x;
        }
        else{
            rank[y] += rank[x];
            parent[x] = y;
        }
    }
    
    int kruskal()
    {
        for(int i = 1; i <= n; i++){
            parent[i] = i;
            rank[i] = 1;
        }
        int ans = 0;
        sort(edge+1, edge+m+1, cmp);
        for(int i = 1, num = 0; num < n-1 && i <= m; i++){
            int x = FindSet(edge[i].u);
            int y = FindSet(edge[i].v);
            if(x != y){
                num++;
                UnionSet(x, y);
                ans += edge[i].w;
            }
        }
        return ans;
    }
    
    int main()
    {
        while(scanf("%d", &n), n){
            m = 0;
            for(int i = 1; i < n; i++){
                int k;
                scanf("%*s%d", &k);
                while(k--){
                    m++;
                    edge[m].u = i;
                    char v[2];
                    scanf("%s%d", v, &edge[m].w);
                    edge[m].v = v[0] - 'A' + 1;
                    //printf("Edge %d : u = %d v = %d w = %d
    ", m, edge[m].u, edge[m].v, edge[m].w);
                }
            }
            printf("%d
    ", kruskal());
        }
        return 0;
    }
  • 相关阅读:
    SharePoint Error occurred in deployment step 'Recycle IIS Application Pool': 0x80070005:拒绝访问
    Getting SharePoint objects (spweb, splist, splistitem) from url string
    SharePoint 2010用“localhost”方式访问网站,File not found问题处理方式
    在 SharePoint 2010 打开网页出错时,显示实际的错误信息
    解决 SharePoint 2010 拒绝访问爬网内容源错误的小技巧(禁用环回请求的两种方式)
    SQL Server 删除数据库所有表和所有存储过程
    SQL Server 查询数据库表的列数
    SQL Server 自定义字符串分割函数
    sp_configure命令开启组件Agent XPs,数据库计划(Maintenance Plan)
    SQL Server 2008 收缩日志(log)文件
  • 原文地址:https://www.cnblogs.com/quasar/p/5142106.html
Copyright © 2011-2022 走看看