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  • 2018 焦作网络赛 K Transport Ship ( 二进制优化 01 背包 )

    题目链接

    题意 : 给出若干个物品的数量和单个的重量、问你能不能刚好组成总重 S

    分析 :

    由于物品过多、想到二进制优化

    其实这篇博客就是存个二进制优化的写法

    关于二进制优化的详情、百度一下有更多资料

    #include<bits/stdc++.h>
    #define LL long long
    #define ULL unsigned long long
    
    #define scl(i) scanf("%lld", &i)
    #define scll(i, j) scanf("%lld %lld", &i, &j)
    #define sclll(i, j, k) scanf("%lld %lld %lld", &i, &j, &k)
    #define scllll(i, j, k, l) scanf("%lld %lld %lld %lld", &i, &j, &k, &l)
    
    #define scs(i) scanf("%s", i)
    #define sci(i) scanf("%d", &i)
    #define scd(i) scanf("%lf", &i)
    #define scIl(i) scanf("%I64d", &i)
    #define scii(i, j) scanf("%d %d", &i, &j)
    #define scdd(i, j) scanf("%lf %lf", &i, &j)
    #define scIll(i, j) scanf("%I64d %I64d", &i, &j)
    #define sciii(i, j, k) scanf("%d %d %d", &i, &j, &k)
    #define scddd(i, j, k) scanf("%lf %lf %lf", &i, &j, &k)
    #define scIlll(i, j, k) scanf("%I64d %I64d %I64d", &i, &j, &k)
    #define sciiii(i, j, k, l) scanf("%d %d %d %d", &i, &j, &k, &l)
    #define scdddd(i, j, k, l) scanf("%lf %lf %lf %lf", &i, &j, &k, &l)
    #define scIllll(i, j, k, l) scanf("%I64d %I64d %I64d %I64d", &i, &j, &k, &l)
    
    #define lson l, m, rt<<1
    #define rson m+1, r, rt<<1|1
    #define lowbit(i) (i & (-i))
    #define mem(i, j) memset(i, j, sizeof(i))
    
    #define fir first
    #define sec second
    #define VI vector<int>
    #define ins(i) insert(i)
    #define pb(i) push_back(i)
    #define pii pair<int, int>
    #define VL vector<long long>
    #define mk(i, j) make_pair(i, j)
    #define all(i) i.begin(), i.end()
    #define pll pair<long long, long long>
    
    #define _TIME 0
    #define _INPUT 0
    #define _OUTPUT 0
    clock_t START, END;
    void __stTIME();
    void __enTIME();
    void __IOPUT();
    using namespace std;
    const int maxn = 1e6 + 10;
    const LL mod = 1e9 + 7;
    
    int num = 0;
    LL w[maxn];
    LL dp[maxn];
    
    int main(void){__stTIME();__IOPUT();
    
        int nCase;
        sci(nCase);
    
        while(nCase--){
    
            num = 0;
    
            int n, q;
            scii(n, q);
    
            for(int i=0; i<n; i++){
                int V, C;
                scii(V, C);
                int tot = (1<<C)-1;
                int j;
    
                for(j=1; j<=tot; j<<=1)
                    w[num++] = 1LL * j * (LL)V % mod, tot -= j;
    
                if(tot > 0){
                    LL rem = tot;
                    w[num++] = 1LL * rem * (LL)V % mod;
                }
            }
    
            mem(dp, 0);
            dp[0] = 1;
    
            for(int i=0; i<num; i++)
                for(int j=(int)1e4; j>=w[i]; j--)
                    dp[j] = (dp[j] + dp[j-w[i]]) % mod;
    
            while(q--){
                int num;
                sci(num);
                printf("%lld
    ", dp[num]);
            }
        }
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    __enTIME();return 0;}
    
    
    void __stTIME()
    {
        #if _TIME
            START = clock();
        #endif
    }
    
    void __enTIME()
    {
        #if _TIME
            END = clock();
            cerr<<"execute time = "<<(double)(END-START)/CLOCKS_PER_SEC<<endl;
        #endif
    }
    
    void __IOPUT()
    {
        #if _INPUT
            freopen("in.txt", "r", stdin);
        #endif
        #if _OUTPUT
            freopen("out.txt", "w", stdout);
        #endif
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/qwertiLH/p/9676688.html
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