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  • c无聊编程

    #include<stdio.h>
    #include<math.h>
    
    void fun_1()//绘制余弦直线
    {
        double y;
        int m, x;
        for (y = 1; y >= -1; y -= 0.1)
        {
            m = acos(y)*10;
            for (x = 1; x < m; x++)printf(" ");
            printf("*");
            for (; x < 62 - m; x++)printf(" ");
            printf("*
    ");
        }
        int x_1, y_1;
        x_1 = 0;
        for (y_1 = 0; y_1 <= 10; y_1++) 
            for(x_1=0;x_1<=y_1;x_1++){
           if(x_1==y_1) {
                printf("*
    ");
                
            }
           else {
               printf(" ");
               
           }
        }
    }
    void fun_2() {
        int i, max, min, sum=0, num[4] = {20,90,85,84};
        max = min = num[0];
        printf("max%d
    ", max);    printf("min%d
    ", min);
        printf("score:
    ");
        for (i = 0; i < 4; i++)
        printf("%d
    ", num[i]);
        for (i = 0; i < 4; i++)
        {
            
            sum += num[i];
            if (max < num[i])
            {
                max = num[i];
                
            }
            if (min > num[i])min = num[i];
        }
        sum = sum - max - min;
        printf("avg%dmin%dmax%d", sum / 2,min,max);
    }
    void fun_3() {
        int i;
        long j;//N的数值
        j = 555555;
        for (i = 999; i > 100; i--)
        {
            if (j%i == 0)
            {
                printf("factor:%d", i);
                break;
            }
        }
    
    }
    void fun_4() {
        int x, y,last=1;
        x = 13;
        for (y = 13; y > 0; y--)
        {
            last = last*x%1000;
        }
        printf("%d",last);
    }
    void fun_5()
    {
        int a, count = 0;
        for (a = 5; a <= 100; a = a + 5)
        {
            count++;
            if (!(a % 25))count++;
        }
        printf("%d",count);
    }
    void fun_6()
    {
        int a, b, c, count=0;
        for (a = 1; a <= 5; a++)
            for (b = 1; b <= 5; b++)
                for (c = 1; c <= 5 && a != b; c++)
                    if (c != a&&c != b)count++;
        printf("%d",count);
    }
    void fun_7()
    {
        int n = 13,i,j;
        for (i = 0; i < n; i++) {
            for (j = 0; j < 12-i; j++)printf(" ");
            for (j = 1; j < i + 2; j++)printf("%6d", fun_7_f(i, j));
            printf("
    ");
        }
    }
    int fun_7_f(int x,int y)//fun_7子函数进行递归
    {
        int z;
        if (y == 1 || y ==x + 1)return 1;
        z = (x - 1, y - 1) + (x - 1, y); return z;
    }
    void fun_8()
    {
        int data[16];
        int i = 0;
        int x=98;
        printf("%d
    ", x);
        for (i = 0;i<8; i++)
        {
            data[i] = x % 2;
            x = x / 2;// printf("%d
    ", x);
            //printf("%d
    ", data[i]);
        }
        for (i = 8; i > 0; i--)
        {
            if (data[i] == 1)
                for (; i >= 0; i--)printf("%d", data[i]);
        }
    }
    
    struct data {
        int year;
        int mouth;
        int day;
    };
    void fun_2_1()
    {
        struct data trem;
        trem.year = 1991;
        trem.mouth = 10;
        trem.day = 25;
        int day_tab[2][12]={ {31,28,31,30,31,30,31,31,30,31,30,31},{ 31,29,31,30,31,30,31,31,30,31,30,31 }    };
        int i, yearf, mouthf, dayf; yearf = mouthf = dayf = 0;
        for (i = trem.year; i > 1991; i--)
        {
            if (i % 4 == 0 && i % 100 != 0)
                dayf =dayf+366;
            else dayf = dayf + 365; printf("year+%d
    ", dayf);
        }
        for (i = 0; i <trem.mouth-1; i++)
        {
            if (trem.year % 4 == 0 && trem.year% 100 != 0)
                dayf = dayf + day_tab[1][i];
            else dayf = dayf + day_tab[0][i]; printf("mouthday+%d
    ", dayf);
        }
        dayf = dayf + trem.day;
        printf("mouthday+%d
    ", dayf);
        
        int f;
        f = dayf % 5;
        printf("%d", f);
        switch (f)
        {
        case 1:;
        case 2:;
        case 3:printf("flash"); break;
        default:printf("sleep");
        }
    
    
    }
    void fun_2_2() {
        
        int i, j, k, l;
        for (i = 1; i < 10; i++) {
    
            for (j = 1; j < 10; j++)
            {
                if (i != j)
                {
                    k = i * 1000 + i * 100 + j * 10 + j;
                    for (l = 31; l*l < k; l++);
                    if (l*l == k)printf("OK	%d", k);
                }
            }
    
        }
    }
    int main()
    {
        
        //fun_1();//绘制余弦直线
        //fun_2();//歌星大奖赛
        //fun_3();//求最大约数
        //fun_4();//高次方数的尾数
        //fun_5();//阶层尾数0个数
        //fun_6();//三个小朋友分五本书
        //fun_7();//杨辉三角
        //fun_8();//二进制转换
        //fun_2_1();//三天打鱼两天晒网
        //fun_2_2();//根据描述追踪车牌号
        fun_2_3();
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/qxhn/p/6110531.html
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