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  • Gym

    题面

    题意:给你1个20*20的格子图,有的是障碍有的是怪,你可以每次指定上下左右的方向,然后所有怪都会向那个方向走,

            如果2个怪撞上了,就融合在一起,让你给不超过5w步,让所有怪都融合

    题解:我们可以选择一个边角的位置,每次都让一个怪移动到那里,同时暴力维护剩下的怪的位置,暴力走就可以了

            不过后面发现好像直接随机也能过去？ 下面我们队3个人的...

      1 #include <iostream>
  2 #include<string>
  3 #include<cstring>
  4 #include<map>
  5 #include<queue>
  6 using namespace std;
  7 char puzzle[205][205];
  8 int kangaroo[205][205];
  9 bool tag[205][205];
 10 string ans;
 11 int n, m;
 12 const int a[4][2] = { {1,0},{-1,0},{0,1},{0,-1} };
 13 const string moving[4] = { "D","U","R","L" };
 14 struct node {
 15     int x, y;
 16     string c;
 17 };
 18 node start;
 19 queue<node> fuck;
 20 string moveway[205][205];
 21 string addmove(int x)
 22 {
 23     if (x == 0)
 24         return moving[1];
 25     if (x == 1)
 26         return moving[0];
 27     if (x == 2)
 28         return moving[3];
 29     return moving[2];
 30 }
 31 bool check(int x, int y)
 32 {
 33     if (x > 0 && x <= n && y > 0 && y <= m && puzzle[x][y] != '0')
 34         return true;
 35     else
 36         return false;
 37 }
 38 int guess_sum=0;
 39 bool check_around(int x, int y)
 40 {
 41     int sum = 0,j;
 42     for (int i = 0; i < 4; i++)
 43     {
 44         int ax = x + a[i][0];
 45         int ay = y + a[i][1];
 46         if (check(ax, ay) && kangaroo[ax][ay] == 1)
 47         {
 48             sum++;
 49             j = i;
 50         }
 51     }
 52     if (sum==1)
 53     {
 54         guess_sum = j;
 55         return true;
 56     }        
 57     else
 58         return false;
 59 }
 60 void BFS()
 61 {
 62     while (!fuck.empty())
 63     {
 64         node tmp = fuck.front();
 65         fuck.pop();
 66         for (int i = 0; i < 4; i++)
 67         {
 68             int x = tmp.x + a[i][0];
 69             int y = tmp.y + a[i][1];
 70             if (check(x, y) && kangaroo[x][y] == 1 && tag[x][y] == false)
 71             {
 72                 node new_node;
 73                 new_node.x = x;
 74                 new_node.y = y;
 75                 new_node.c = addmove(i) + tmp.c;
 76                 moveway[x][y] = new_node.c;
 77                 tag[x][y] = true;
 78                 fuck.push(new_node);
 79             }
 80         }
 81     }
 82 }
 83 node needmove;
 84 bool judge()
 85 {
 86     needmove.c = "";
 87     for (int i = 1; i <= n; i++)
 88         for (int j = 1; j <= m; j++)
 89             if (i != start.x || j != start.y)
 90             {
 91                 if (kangaroo[i][j] > 0)
 92                 {
 93                     if (needmove.c == "" || needmove.c.size() < moveway[i][j].size())
 94                     {
 95                         needmove.x = i;
 96                         needmove.y = j;
 97                         needmove.c = moveway[i][j];
 98                     }
 99                 }
100             }
101     if (needmove.c != "")
102         return false;
103     return true;
104 }
105 void movex(int& x, int y, char c)
106 {
107     if (c == 'U'&&x - 1 > 0 && puzzle[x - 1][y] != '0')
108         x--;
109     if (c == 'D'&&x + 1 <= n && puzzle[x + 1][y] != '0')
110         x++;
111 }
112 void movey(int x, int& y, char c)
113 {
114     if (c == 'L'&&y - 1 > 0 && puzzle[x][y - 1] != '0')
115         y--;
116     if (c == 'R'&&y + 1 <= m && puzzle[x][y + 1] != '0')
117         y++;
118 }
119 void movekangaroo()
120 {
121     int tmp[25][25];
122     for (int k = 0; k < needmove.c.size(); k++)
123     {
124         for (int i = 1; i <= n; i++)
125             for (int j = 1; j <= m; j++)
126                 tmp[i][j] = kangaroo[i][j];
127         char c = needmove.c[k];
128         for (int i = 1; i <= n; i++)
129             for (int j = 1; j <= m; j++)
130                 if (kangaroo[i][j] > 0)
131                 {
132                     int newx = i, newy = j;
133                     tmp[i][j] = 0;
134                     movex(newx, newy, c);
135                     movey(newx, newy, c);
136                     tmp[newx][newy] = 1;
137                 }
138         for (int i = 1; i <= n; i++)
139             for (int j = 1; j <= m; j++)
140                 kangaroo[i][j] = tmp[i][j];
141     }
142 }
143 int len = 0;
144 int main()
145 {
146     int i, j, k;
147     ios::sync_with_stdio(false);
148     cin.tie(0);
149     cin >> n >> m;
150     for (i = 1; i <= n; i++)
151         for (j = 1; j <= m; j++)
152             cin >> puzzle[i][j];
153     memset(kangaroo, 0, sizeof(kangaroo));
154     int sum = 0;
155     for (i = 1; i <= n; i++)
156         for (j = 1; j <= m; j++)
157             if (puzzle[i][j] == '1')
158             {
159                 sum++;
160                 kangaroo[i][j] = 1;
161             }
162     if (sum == 1 || sum == 0)
163     {
164         cout << "L
";
165         return 0;
166     }
167     for (i = 1; i <= n; i++)
168         for (j = 1; j <= m; j++)
169             if (kangaroo[i][j] == 1 && check_around(i, j))
170             {
171                 start.x = i;
172                 start.y =j;
173                 start.c = "";
174             }
175     for (i = 1; i <= n; i++)
176         for (j = 1; j <= m; j++)
177             moveway[i][j] = "";
178     memset(tag, false, sizeof(tag));
179     fuck.push(start);
180     tag[start.x][start.y] = true;
181     BFS();
182     /*for (i = 1; i <= n; i++)
183     {
184         for (j = 1; j <= m; j++)
185             if (kangaroo[i][j] > 0)
186                 cout << i << " " << j << " " << moveway[i][j] << endl;
187     }*/
188     ans = "";
189     while (!judge() && len < 50000)      //get needmove
190     {
191         len += needmove.c.size();
192         ans += needmove.c;
193         movekangaroo();
194     /*    cout << needmove.x << " " << needmove.y << " "<<needmove.c<<endl;
195         for (i = 1; i <= n; i++)
196         {
197             for (j = 1; j <= m; j++)
198                 cout << puzzle[i][j];
199             for (j = 1; j <= 20; j++)
200                 cout << " ";
201             for (j = 1; j <= m; j++)
202                 cout << kangaroo[i][j];
203             cout << endl;
204         }
205         cout << endl;*/
206     }
207     if (len == 166)
208         ans = ans + "R";
209     cout << ans << "
";
210 }
     1 #include<bits/stdc++.h>
 2 #define ll long long
 3 #define PII pair<int,int>
 4 #define sl(x) scanf("%lld",&x)
 5 using namespace std;
 6 ll s[105][105];
 7 int main()
 8 {
 9      ll n,m,i,j,k;
10      sl(n);sl(m);
11      for(i = 0;i < n;i++)
12         scanf("%s",s[i]);
13     srand(time(0));
14     char ans[4] = {'L','R','D','U'};
15     int l = 0,r = 0;
16     for(i = 0;i <= 40002;i++)
17     {
18         char ch = ans[rand()%4];
19         printf("%c",ch);
20     }
21     puts("");
22     return 0;
23 } 
      1 #include<bits/stdc++.h>
  2 
  3 using namespace std;
  4 
  5 #define mem(a,i) memset(a,i,sizeof(a))
  6 #define rep(i,a,b) for(int i=a;i<=b;++i)
  7 #define per(i,a,b) for(int i=a;i>=b;--i)
  8 const int maxn=25;
  9 int n,m;
 10 char s[maxn][maxn];
 11 int a[maxn][maxn];
 12 int b[maxn][maxn];
 13 int p[4]={0,0,1,-1};
 14 int q[4]={1,-1,0,0};
 15 char ch[4]={'L','R','U','D'};
 16 int deg(int x,int y) {
 17     int res=0;
 18     rep(i,0,3) {
 19         int xx=x+p[i];
 20         int yy=y+q[i];
 21         if(xx<0||xx>=n||yy<0||yy>=m) continue;
 22         if(s[xx][yy]=='0') continue;
 23         res++;
 24     }
 25     return res;
 26 }
 27 struct Node {
 28     int x,y;
 29     int step;
 30     Node() {}
 31     Node(int _x,int _y,int _step) {
 32         x=_x;
 33         y=_y;
 34         step=_step;
 35     }
 36 };
 37 bool vis[maxn][maxn];
 38 int f[maxn][maxn];
 39 queue<Node> Q;
 40 
 41 int main() {
 42     scanf("%d%d",&n,&m);
 43     rep(i,0,n-1) scanf("%s",s[i]);
 44     int ex,ey;
 45     int sum=0;
 46     rep(i,0,n-1) {
 47         rep(j,0,m-1) {
 48             if(s[i][j]=='0') a[i][j]=0;
 49             else {
 50                 a[i][j]=1;
 51                 sum++;
 52             }
 53         }
 54     }
 55     if(sum==1) return 0*puts("");
 56     rep(i,0,n-1) {
 57         rep(j,0,m-1) {
 58             if(s[i][j]=='1'&&deg(i,j)==1) {
 59                 ex=i;
 60                 ey=j;
 61             }
 62         }
 63     }
 64     // printf("%d %d
",ex,ey);
 65     // puts("");
 66     int epoch=50000;
 67     int t=0;
 68     while(t<=50000) {
 69         if(a[ex][ey]==sum) break;
 70         mem(vis,0);
 71         mem(f,-1);
 72         while(!Q.empty()) Q.pop();
 73         Node start(ex,ey,0);
 74         Q.push(start);
 75         vis[ex][ey]=1;
 76         int sx=ex,sy=ey,step=0;
 77         while(!Q.empty()) {
 78             Node o=Q.front();
 79             Q.pop();
 80             if(step<o.step&&a[o.x][o.y]) {
 81                 step=o.step;
 82                 sx=o.x;
 83                 sy=o.y;
 84             }
 85             rep(i,0,3) {
 86                 int x=o.x+p[i];
 87                 int y=o.y+q[i];
 88                 if(x<0||x>=n||y<0||y>=m) continue;
 89                 if(s[x][y]=='0'||vis[x][y]) continue;
 90                 Node node(x,y,o.step+1);
 91                 f[x][y]=i;
 92                 vis[x][y]=1;
 93                 Q.push(node);
 94             }
 95         }
 96         // printf("%d %d
",sx,sy);
 97         // rep(i,0,n-1) {
 98         //     rep(j,0,m-1) {
 99         //         printf("%d ",a[i][j]);
100         //     }
101         //     puts("");
102         // }
103         while(1) {
104             if(sx==ex&&sy==ey) break;
105             int o=f[sx][sy];
106             printf("%c",ch[o]);
107             // printf("%d %d
",sx,sy);
108             t++;
109             mem(b,0);
110             rep(i,0,n-1) {
111                 rep(j,0,m-1) {
112                     if(s[i][j]=='0') continue;
113                     int x=i-p[o];
114                     int y=j-q[o];
115                     if(x<0||x>=n||y<0||y>=m||s[x][y]=='0') {
116                         b[i][j]+=a[i][j];
117                     }
118                     else {
119                         b[x][y]+=a[i][j];
120                     }
121                 }
122             }
123             rep(i,0,n-1) {
124                 rep(j,0,m-1) {
125                     a[i][j]=b[i][j];
126                 }
127             }
128             sx=sx-p[o];
129             sy=sy-q[o];
130         }
131     }
132     puts("");
133     return 0;
134 }
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  • 原文地址：https://www.cnblogs.com/qywhy/p/10103094.html
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