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  • poj1037

    dp

    很复杂,具体参见黑书p257页。

    View Code
    #include <iostream>
    #include
    <cstdio>
    #include
    <cstdlib>
    #include
    <cstring>
    using namespace std;

    #define maxn 30

    struct Node
    {
    long long up, down;
    } g[maxn][maxn];

    long long n;
    long long c;
    long long ans[maxn];

    void getfirst(long long n, long long c, bool u)
    {
    if (n == 0)
    return;
    long long t;
    long long sum;
    if (!u)
    {
    sum
    = 0;
    t
    = ans[n + 1];
    while (sum + g[n][t].down < c)
    {
    sum
    += g[n][t].down;
    t
    ++;
    }
    }
    else
    {
    sum
    = 0;
    t
    = 1;
    while (sum + g[n][t].up < c)
    {
    sum
    += g[n][t].up;
    t
    ++;
    }
    }
    ans[n]
    = t;
    getfirst(n
    - 1, c - sum, !u);
    for (long long i = 1; i < n; i++)
    if (ans[i] >= t)
    ans[i]
    ++;
    }

    int main()
    {
    //freopen("t.txt", "r", stdin);
    g[1][1].up = 1;
    g[
    1][1].down = 1;
    for (long long i = 2; i <= 20; i++)
    {
    for (long long j = 1; j <= i; j++)
    {
    g[i][j].up
    = g[i][j].down = 0;
    for (long long k = j; k <= i - 1; k++)
    g[i][j].up
    += g[i - 1][k].down;
    for (long long k = 1; k <= j - 1; k++)
    g[i][j].down
    += g[i - 1][k].up;
    }
    }
    long long x;
    scanf(
    "%lld", &x);
    while (x--)
    {
    scanf(
    "%lld%lld", &n, &c);

    long long t = 1, sum = 0;
    while (sum + g[n][t].down + g[n][t].up < c)
    {
    sum
    += g[n][t].down + g[n][t].up;
    t
    ++;
    }
    ans[n]
    = t;
    if (sum + g[n][t].down < c)
    getfirst(n
    - 1, c - sum - g[n][t].down, false);
    else
    getfirst(n
    - 1, c - sum, true);
    for (long long i = 1; i < n; i++)
    if (ans[i] >= t)
    ans[i]
    ++;

    printf(
    "%lld", ans[n]);
    for (int i = n - 1; i >= 1; i--)
    printf(
    " %lld", ans[i]);
    putchar(
    '\n');
    }
    return 0;
    }
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  • 原文地址:https://www.cnblogs.com/rainydays/p/2122079.html
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