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  • poj2535

    简单题

    View Code
    #include <iostream>
    #include
    <cstdio>
    #include
    <cstdlib>
    #include
    <cstring>
    using namespace std;

    #define maxn 105

    int n, p;
    int f[maxn];
    bool hard[maxn];
    int point[maxn];

    int main()
    {
    //freopen("t.txt", "r", stdin);
    scanf("%d%d", &n, &p);
    memset(f,
    0, sizeof(f));
    memset(hard,
    0, sizeof(hard));
    for (int i = 0; i < n; i++)
    {
    int s = 0x3f3f3f3f, h = 0;
    for (int j = 0; j < p; j++)
    {
    scanf(
    "%d", &point[j]);
    s
    = min(s, point[j]);
    h
    = max(h, point[j]);
    }
    for (int j = 0; j < p; j++)
    {
    if (s == point[j])
    f[j]
    ++;
    if (h == point[j])
    hard[j]
    = true;
    }
    }
    int i = 0;
    while (i < p && (hard[i] || f[i] <= n / 2))
    i
    ++;
    if (i == p)
    {
    printf(
    "0\n");
    return 0;
    }
    printf(
    "%d", i + 1);
    for (int j = i + 1; j < p; j++)
    if (!hard[j] && f[j] > n / 2)
    printf(
    " %d", j+ 1);
    putchar(
    '\n');
    return 0;
    }
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  • 原文地址:https://www.cnblogs.com/rainydays/p/2124965.html
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