基本的树形dp,需要dfs三次,第一次求每个点最远的后代,第二次和第三次每个点的孩子分别从左到右和从右到左遍历。
#include <cstdio> #include <vector> using namespace std; #define D(x) const int MAX_N = (int)(1e4) + 5; int n; vector <pair<int, int> > edge[MAX_N]; int child[MAX_N]; int father_left[MAX_N]; int father_right[MAX_N]; void dfs_child(int father, int u) { child[u] = 0; for (int i = 0; i < (int)edge[u].size(); i++) { int v = edge[u][i].first; int w = edge[u][i].second; if (v != father) { dfs_child(u, v); child[u] = max(child[u], child[v] + w); } } } void dfs_father_left(int father, int u, int up) { father_left[u] = up; int temp = 0; for (int i = 0; i < (int)edge[u].size(); i++) { int v = edge[u][i].first; int w = edge[u][i].second; if (v != father) { dfs_father_left(u, v, max(up, temp) + w); temp = max(temp, w + child[v]); } } } void dfs_father_right(int father, int u, int up) { father_right[u] = up; int temp = 0; for (int i = (int)edge[u].size() - 1; i >= 0; i--) { int v = edge[u][i].first; int w = edge[u][i].second; if (v != father) { dfs_father_right(u, v, max(up, temp) + w); temp = max(temp, w + child[v]); } } } int main() { while (scanf("%d", &n) != EOF) { for (int i = 1; i <= n; i++) { edge[i].clear(); } for (int i = 2; i <= n; i++) { int a, b; scanf("%d%d", &a, &b); edge[i].push_back(make_pair(a, b)); edge[a].push_back(make_pair(i, b)); } dfs_child(-1, 1); dfs_father_left(-1, 1, 0); dfs_father_right(-1, 1, 0); for (int i = 1; i <= n; i++) { D(printf("%d %d %d ", child[i], father_left[i], father_right[i])); printf("%d ", max(child[i], max(father_left[i], father_right[i]))); } } return 0; }