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  • python元祖(tuple)

    # 列表:有序,元素可以被修改
    # 列表
    # list
    # li = [111,22,33,44]
    
    # 元组:元素不可被修改,不能被增加或者删除
    # ps:
    # tuple
    # tu = (11,22,33,44,22,22)
    # print(tu.count(22)) #获取指定元素在元组中出现的次数
    # print(tu.index(22))
    
    ###########  深灰魔法  ###########
    # 1. 书写格式
    # 一般写元组的时候,推荐在最后加入 ,
    # 元素不可被修改,不能被增加或者删除
    # tu = (111,"raito",(11,22),[(33,44)],True,33,44,)
    # 2. 索引
    # v = tu[0]
    # print(v)
    
    # 3. 切片
    # v = tu[0:2]
    # print(v)
    
    # 4. 可以被for循环,可迭代对象
    # for item in tu:
    #     print(item)
    
    # 5. 转换
    # s = "asdfasdf0"
    # li = ["asdf","asdfasdf"]
    # tu = ("asdf","asdf")
    #
    # v = tuple(s)
    # print(v)
    
    # v = tuple(li)
    # print(v)
    
    # v = list(tu)
    # print(v)
    
    # v = "_".join(tu)
    # print(v)
    
    # li = ["asdf","asdfasdf"]
    # li.extend((11,22,33,))
    # print(li)
    
    # 6.元组的一级元素不可修改/删除/增加
    # tu = (111,"raitorei",(3,4),[(1,2)],True,7,11,)
    # 元组,有序。
    # v = tu[3][0][0]
    # print(v)
    # v=tu[3]
    # print(v)
    # tu[3][0] = 567
    # print(tu)
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  • 原文地址:https://www.cnblogs.com/raitorei/p/11626280.html
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