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  • 坐标系间的转换

    一、各大坐标系

      目前地图开发离不开定位,定位又离不开坐标系的选取和转换,所以有必要简单说一下啦。

    世界大地坐标(WGS84)

      1.国际上采用的标准,是为GPS全球定位系统使用而建立的坐标系统,可从专业GPS设备中获取数据。

      2.国际地图使用的坐标系。

           3.谷歌国外地图、osm地图

    火星坐标(GCJ-02)

      1.中国采用的标准,准确是叫国测局坐标系,可从国行移动设备定位获得数据

      2.国内出版的各类地图都至少采用GCJ-02对地理位置进行加密偏移

      3.高德地图、天地图、搜搜地图等

    百度坐标(BD-09)

      1.百度地图自己采用的坐标标准。

      2.百度坐标是在GCJ-02的基础上再次加密

      3.百度地图

    二、各大坐标系间的转换

    通用实体 

     1     /// <summary>
     2     /// 经度和纬度
     3     /// </summary>
     4     public class StationGps
     5     {
     6         /// <summary>
     7         /// 经度
     8         /// </summary>
     9         public double longitude { get; set; }
    10         /// <summary>
    11         /// 纬度
    12         /// </summary>
    13         public double latitude { get; set; }
    14     }

    1、火星坐标转百度

     1        private static double x_pi = 3.14159265358979324 * 3000.0 / 180.0;
     2 
     3         public static StationGps HxToBd(double lon, double lat)
     4         {
     5             var result = new StationGps();
     6             double x = lon, y = lat;
     7             var z = Math.Sqrt(x * x + y * y) + 0.00002 * Math.Sin(y * x_pi);
     8             var theta = Math.Atan2(y, x) + 0.000003 * Math.Cos(x * x_pi);
     9             result.longitude = z * Math.Cos(theta) + 0.0065;
    10             result.latitude = z * Math.Sin(theta) + 0.006;
    11             return result;
    12         }
    View Code

    2、百度转火星坐标

     1         private static double x_pi = 3.14159265358979324 * 3000.0 / 180.0;
     2           
     3         public static StationGps BdToHx(double lon, double lat)
     4         {
     5             var result = new StationGps();
     6             double x = lon - 0.0065, y = lat - 0.006;
     7             var z = Math.Sqrt(x * x + y * y) - 0.00002 * Math.Sin(y * x_pi);
     8             var theta = Math.Atan2(y, x) - 0.000003 * Math.Cos(x * x_pi);
     9             result.longitude = z * Math.Cos(theta);
    10             result.latitude = z * Math.Sin(theta);
    11             return result;
    12         }
    View Code

    3、世界大地坐标转火星坐标

     1         private static double pi = 3.14159265358979324;
     2         private static double a = 6378245.0;
     3         private static double ee = 0.00669342162296594323; 
     4 
     5         public static StationGps WgsToHx(double lon, double lat)
     6         {
     7             var result = new StationGps();
     8             double dLat = TransformLat(lat - 35.0, lon - 105.0);
     9             double dLon = TransformLon(lat - 35.0, lon - 105.0);
    10             double radLat = lat / 180.0 * pi;
    11             double magic = Math.Sin(radLat);
    12             magic = 1 - ee * magic * magic;
    13             var sqrtMagic = Math.Sqrt(magic);
    14             dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
    15             dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
    16             result.latitude = lat + dLat;
    17             result.longitude = lon + dLon;
    18             return result;
    19         }
    20 
    21         private static double TransformLat(double lon, double lat)
    22         {
    23             var ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.Sqrt(Math.Abs(lat));
    24             ret += (20.0 * Math.Sin(6.0 * lat * pi) + 20.0 * Math.Sin(2.0 * lat * pi)) * 2.0 / 3.0;
    25             ret += (20.0 * Math.Sin(lon * pi) + 40.0 * Math.Sin(lon / 3.0 * pi)) * 2.0 / 3.0;
    26             ret += (160.0 * Math.Sin(lon / 12.0 * pi) + 320 * Math.Sin(lon * pi / 30.0)) * 2.0 / 3.0;
    27             return ret;
    28         }
    29         private static double TransformLon(double lon, double lat)
    30         {
    31             var ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.Sqrt(Math.Abs(lat));
    32             ret += (20.0 * Math.Sin(6.0 * lat * pi) + 20.0 * Math.Sin(2.0 * lat * pi)) * 2.0 / 3.0;
    33             ret += (20.0 * Math.Sin(lat * pi) + 40.0 * Math.Sin(lat / 3.0 * pi)) * 2.0 / 3.0;
    34             ret += (150.0 * Math.Sin(lat / 12.0 * pi) + 300.0 * Math.Sin(lat / 30.0 * pi)) * 2.0 / 3.0;
    35             return ret;
    36         }
    View Code

    4、世界大地坐标转为百度坐标

     1         private static double pi = 3.14159265358979324;
     2         private static double a = 6378245.0;
     3         private static double ee = 0.00669342162296594323;
     4         private static double x_pi = 3.14159265358979324 * 3000.0 / 180.0; 
     5 
     6         public static StationGps WgsToBd(double lon, double lat)
     7         {
     8             var hx = WgsToHx(lon, lat);
     9             var bd = HxToBd(hx.longitude, hx.latitude);
    10             return bd;
    11         }
    12 
    13         public static StationGps HxToBd(double lon, double lat)
    14         {
    15             var result = new StationGps();
    16             double x = lon, y = lat;
    17             var z = Math.Sqrt(x * x + y * y) + 0.00002 * Math.Sin(y * x_pi);
    18             var theta = Math.Atan2(y, x) + 0.000003 * Math.Cos(x * x_pi);
    19             result.longitude = z * Math.Cos(theta) + 0.0065;
    20             result.latitude = z * Math.Sin(theta) + 0.006;
    21             return result;
    22         } 
    23 
    24         public static StationGps WgsToHx(double lon, double lat)
    25         {
    26             var result = new StationGps();
    27             double dLat = TransformLat(lat - 35.0, lon - 105.0);
    28             double dLon = TransformLon(lat - 35.0, lon - 105.0);
    29             double radLat = lat / 180.0 * pi;
    30             double magic = Math.Sin(radLat);
    31             magic = 1 - ee * magic * magic;
    32             var sqrtMagic = Math.Sqrt(magic);
    33             dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
    34             dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
    35             result.latitude = lat + dLat;
    36             result.longitude = lon + dLon;
    37             return result;
    38         }
    39 
    40         private static double TransformLat(double lon, double lat)
    41         {
    42             var ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.Sqrt(Math.Abs(lat));
    43             ret += (20.0 * Math.Sin(6.0 * lat * pi) + 20.0 * Math.Sin(2.0 * lat * pi)) * 2.0 / 3.0;
    44             ret += (20.0 * Math.Sin(lon * pi) + 40.0 * Math.Sin(lon / 3.0 * pi)) * 2.0 / 3.0;
    45             ret += (160.0 * Math.Sin(lon / 12.0 * pi) + 320 * Math.Sin(lon * pi / 30.0)) * 2.0 / 3.0;
    46             return ret;
    47         }
    48 
    49         private static double TransformLon(double lon, double lat)
    50         {
    51             var ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.Sqrt(Math.Abs(lat));
    52             ret += (20.0 * Math.Sin(6.0 * lat * pi) + 20.0 * Math.Sin(2.0 * lat * pi)) * 2.0 / 3.0;
    53             ret += (20.0 * Math.Sin(lat * pi) + 40.0 * Math.Sin(lat / 3.0 * pi)) * 2.0 / 3.0;
    54             ret += (150.0 * Math.Sin(lat / 12.0 * pi) + 300.0 * Math.Sin(lat / 30.0 * pi)) * 2.0 / 3.0;
    55             return ret;
    56         } 
    View Code
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  • 原文地址:https://www.cnblogs.com/raniynight/p/8522823.html
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