Rotate Image
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Follow up:
Could you do this in-place?
假设旋转的时候,左上角元素为(l,l),右下角元素为(r,r)
则旋转的时候
(l,l+1)=(r-1,l) 最上面一排
(r-1,l)=(r,r-1)左边一排
(r,r-1)=(l+1,r)下面一排
(l+1,r)=(l,l+1)右边一排
可以找到规律
(i,j)--->(r+l-j,i)
1 class Solution { 2 public: 3 void rotate(vector<vector<int> > &matrix) { 4 5 int n=matrix.size(); 6 int leftUp=0; 7 int rightBottom=n-1; 8 while(rightBottom>leftUp) 9 { 10 int n0=rightBottom+leftUp; 11 for(int i=leftUp;i<rightBottom;i++) 12 { 13 int tmp=matrix[leftUp][i]; 14 matrix[leftUp][i]=matrix[n0-i][leftUp]; 15 matrix[n0-i][leftUp]=matrix[n0-leftUp][n0-i]; 16 matrix[n0-leftUp][n0-i]=matrix[i][n0-leftUp]; 17 matrix[i][n0-leftUp]=tmp; 18 19 } 20 21 leftUp++;rightBottom--; 22 } 23 } 24 };