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  • 167. Two Sum II

    Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.

    The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.

    Note:

    • Your returned answers (both index1 and index2) are not zero-based.
    • You may assume that each input would have exactly one solution and you may not use the same element twice.

    Example:

    Input: numbers = [2,7,11,15], target = 9
    Output: [1,2]
    Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.

    这道题刚做的时候不知道题目让我返回什么...大小为 returnSize 的数组,返回值是个指针,这个指针指向一个长度为 returnSize 的 int 数组。

     1 /**
     2 * Return an array of size *returnSize.
     3 * Note: The returned array must be malloced, assume caller calls free().
     4 */
     5 int* twoSum(int* numbers, int numbersSize, int target, int* returnSize) {
     6     int mid,low=0,high=numbersSize-1,sum;
     7     int *nums=(int*)malloc(sizeof(int)*2); 
     8     while(low<=high){
     9         sum=numbers[low]+numbers[high];
    10         if(sum==target){
    11             nums[0]=low+1;
    12             nums[1]=high+1;
    13             break;
    14         }    
    15         else if(sum<target)    low++;
    16         else high--;
    17     }
    18     *returnSize=2;
    19     return nums;
    20 }
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  • 原文地址:https://www.cnblogs.com/real1587/p/9786925.html
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