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  • 278. First Bad Version

    You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

    Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

    You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

    Example:

    Given n = 5, and version = 4 is the first bad version.
    
    call isBadVersion(3) -> false
    call isBadVersion(5) -> true
    call isBadVersion(4) -> true
    
    Then 4 is the first bad version. 
     1 // Forward declaration of isBadVersion API.
     2 //二分查找
     3 bool isBadVersion(int version);
     4 /*如果w​​hile语句在left == right时运行,它会进入无限循环,因为它始终是if(isBadVersion(mid)){right = mid; }。因此,要退出while语句,它应该保持<right,以便在它= = right时退出。*/
     5 int firstBadVersion(int n) {
     6     int left=1,right=n;
     7     while (left < right) {
     8         int mid = left + (right - left) / 2;
     9         if (isBadVersion(mid)) {
    10             right = mid;
    11         } else {
    12             left = mid + 1;
    13         }
    14     }
    15     return left;
    16 }
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  • 原文地址:https://www.cnblogs.com/real1587/p/9787400.html
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