237. Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list -- head = [4,5,1,9], which looks like following:

    4 -> 5 -> 1 -> 9

Example 1:

Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list
             should become 4 -> 1 -> 9 after calling your function.

Example 2:

Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list
             should become 4 -> 5 -> 9 after calling your function.

Note:

• The linked list will have at least two elements.
• All of the nodes' values will be unique.
• The given node will not be the tail and it will always be a valid node of the linked list.
• Do not return anything from your function.
  删除除了尾部外的链表中的值，一开始的做法没有考虑到释放内存，只是简单的移动赋值，奇怪的居然也AC了。
  

  void deleteNode(struct ListNode* node) {
      if(node){
          node->val=node->next->val;
          node->next=node->next->next;
      }
  }

  在讨论区看到别人更好的做法

  void deleteNode(struct ListNode* node) {
      if(node){
          struct ListNode *next=node->next;
          *node=*next;
          free(next);
      }
  }