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  • 第二次上机练习

    1.编写程序, 输入变量x的值,如果是1,输出x=1,如果是5,输出x=5,如果是 10,输出 x=10,除了以上几个值,都输出x=none。(知识点:if条件语句)

    package huaerzi;
    import java.util.Scanner;
    public class huada {
        public static void main(String[] args) {
              // TODO Auto-generated method stub
             Scanner in =new Scanner(System.in);
             System.out.println("请输入数字:");{
                int a = in.nextInt();
                if(a==1 || a==5 || a==10) {
                    System.out.println("x="+a);
                }else {
                 System.out.println("x=none");}
        }
    }
    }

    2.用switch结构实现第1题

    package huaerzi;
    import java.util.Scanner;
    public class huada {
        public static void main(String[] args) {
              // TODO Auto-generated method stub
            Scanner huaer= new Scanner(System.in);
            System.out.println("请输入a的值");
            int a=huaer.nextInt();
            switch(a) {
            case 1: 
            case 5: 
            case 10:
                System.out.println("a="+a);break;
            default:
                System.out.println("a=none");
                 System.out.println("a=none");}
        }
    }

    3.判断一个数字是否能被5和6同时整除(打印能被5和6整除),或只能被5整除(打印能被5整 除),或只能被6整除,(打印能被6整除),不能被5或6整除,(打印不能被5或6整除)

    package huaerzi;
    import java.util.Scanner;
    public class huada {
        public static void main(String[] args) {
              // TODO Auto-generated method stub
            System.out.println("请输入一个整数");
            Scanner scanner = new Scanner(System.in);
            int a = scanner.nextInt();
            if (a % 5 == 0 && a % 6 == 0) {
            System.out.println("您输入的数字" +a + "能被5和6整除");
            } else if (a % 5 == 0) {
            System.out.println("您输入的数字" + a + "能被5整除");
            } else if (a % 6 == 0) {
            System.out.println("您输入的数字" + a + "能被6整除");
            } else {
            System.out.println("您输入的数字不能被5或6整除");
            }
        }
    }

    4.输入一个0~100的分数,如果不是0~100之间,打印分数无效,根据分数等级打印 A(90-100),B(80-89),C,D,E(知识点:条件语句if elseif)

    package huaerzi;
    import java.util.Scanner;
    public class huada {
        public static void main(String[] args) {
              // TODO Auto-generated method stub
            System.out.println("请输入一个整数");
            Scanner scanner = new Scanner(System.in);
            int grade = scanner.nextInt();
             if ((grade>100)||(grade<0)) {
            System.out.println("无效");
            } else if ((grade>=80)&&(grade<90)) {
            System.out.println("B");
            } else if ((grade>=90)&&(grade<=100)) {
            System.out.println("A");
            } else  if ((grade>=70)&&(grade<80)){
            System.out.println("C");
            } else if ((grade>=60)&&(grade<70)){
            System.out.println("D");
            }else System.out.println("E");
        }
    }

    5.输入三个整数x,y,z,请把这三个数由小到大输出(知识点:条件语句)

    package huaerzi;
    import java.util.Scanner;
    public class huada {
        public static void main(String[] args) {
              // TODO Auto-generated method stub
            Scanner sc  = new Scanner(System.in);
            System.out.println("输入三个数");
                    int x = sc.nextInt();
                    int y = sc.nextInt();
                    int z = sc.nextInt();
                    if(x>y){
                        if(y>z){
                            System.out.println(x+","+y+","+z);
                        }else if(x<z){
                            System.out.println(z+","+x+","+y);
                        }else{
                            System.out.println(x+","+z+","+y);
        
                        }
                    }else if(y>x){
                        if(x>z){
                            System.out.println(y+","+x+","+z);
                        }else if(y<z){
                            System.out.println(z+","+y+","+x);
                        }else{
                            System.out.println(y+","+z+","+x);
    
                        }
                    }
        }
    
    }
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  • 原文地址:https://www.cnblogs.com/reddead/p/12573303.html
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