python匹配ip正则

python匹配ip正则

#！/usr/bin/env python  
# -*- coding:utf-8 -*-  
import re  
ip_str = "asdad1.1.1.1sdfwe2.6.5.7sdfsf2.3.94.5sdf200.198.25.0"  
res = []  
for i in range(1):  
  
    ip_t = True  
    m_ind = 0  
    while ip_t:  
        m = re.search(r"(((2([0-4]d|5[0-5])|((1d|[1-9])?d)|d).){3}(2([0-4]d|5[0-5])|(1d|[1-9])?d|d))",ip_str[m_ind:])  
        if m:  
            msum = m.group()  
            res.append(msum)  
            m_ind = ip_str.index(msum) + len(msum) -1  
        else:  
            ip_t = False  
  
print(res)  
#print(msum,m_ind)  

思路

图片有错误，但思路正确，代码和图片对比，放这个是为了对比思路，赞这个图片的人的思路，着实牛 

 shell grep 过滤所有ip

cat abc | grep -Po "(^10.(1d{2}|2[0-4]d|25[0-5]|[1-9]d|[0-9]).(1d{2}|2[0-4]d|25[0-5]|[1-9]d|[0-9]).(1d{2}|2[0-4]d|25[0-5]|[1-9]d|[0-9])$)|(^172.(1[6789]|2[0-9]|3[01]).(1d{2}|2[0-4]d|25[0-5]|[1-9]d|[0-9]).(1d{2}|2[0-4]d|25[0-5]|[1-9]d|[0-9])$)|(^192.168.(1d{2}|2[0-4]d|25[0-5]|[1-9]d|[0-9]).(1d{2}|2[0-4]d|25[0-5]|[1-9]d|[0-9])$)"