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  • 2. Add Two Numbers

    You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

    Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
    Output: 7 -> 0 -> 8

     public ListNode AddTwoNumbers(ListNode l1, ListNode l2) {
            /*if (l1 == null) return l2;
            if (l2 == null) return l1;
            ListNode newNode = new ListNode(0);
            ListNode nextNode = new ListNode(0);
            newNode.val = (l1.val + l2.val)%10;
            newNode.next = nextNode;
            nextNode =  AddTwoNumbers( l1.next,  l2.next);
            nextNode.val +=((l1.val + l2.val)/10 ==1)? 1 : 0;*/
            //return AddTwoNumbers(l1,l2,0);
            ListNode result = new ListNode(0);
        int add = 0;
        if(l1 == null) return l2;
        if(l2 == null) return l1;
        int sum =0;
        ListNode stand = result;
        while((l1 != null)||(l2 != null))
         {
              if(l1 != null)
            {
                sum += l1.val; 
                l1 = l1.next;
            }
            if(l2 != null)
            {
                sum += l2.val; 
                l2 = l2.next;
            }
            //sum+=add;
            
            result.next =  new ListNode(sum%10);
            result = result.next;
            sum = sum/10;
    
         }    
        //judge highest digit add or not
        result.next = (sum==1)?new ListNode(1):null;
    
        return stand.next; 
    }
            
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  • 原文地址:https://www.cnblogs.com/renyualbert/p/5855606.html
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