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  • python3使用stmplib发送邮件

    代码如下:

    import smtplib
    from email.mime.text import MIMEText
    from email.header import Header
    from email.utils import formataddr
    
    # 第三方 SMTP 服务
    mail_host = "smtp.exmail.qq.com"
    mail_port = 465  # 也可能是25,看情况。SMTPS的话一般是465
    mail_user = "a@a.com"
    mail_pass = "aaa"   # 密码或邮箱授权码
    
    mail_sender = 'a@a.com'
    mail_receivers = ['a@a.com']
    
    subject = '邮件主题'
    message = MIMEText('邮件内容', 'plain', 'utf-8')  # plain表示邮件类型
    message['From'] = formataddr(["发件人别称", "a@a.com"])
    message['To'] = formataddr(["收件人别称", "a@a.com"])
    message['Subject'] = Header(subject, 'utf-8')
    
    
    def sendmail(host, port, sender, password, recvivers, meassage):
        try:
            mail_obj = smtplib.SMTP_SSL()  # 邮件服务器使用 SMTPS 的时候用 SMTP_SSL
            mail_obj.connect(host, port)
            mail_obj.login(sender, password)
            mail_obj.sendmail(sender, recvivers, meassage.as_string())
            mail_obj.quit()
            print("Send sucessful")
            return True
        except Exception as e:
            err = "Send Failed for reason:
     {}".format(e)
            print(err)
            return False
    
    
    sendmail(mail_host, mail_port, mail_sender, mail_pass, mail_receivers, message)
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  • 原文地址:https://www.cnblogs.com/resn/p/7279906.html
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