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  • 批量替换文件名和内容的Python脚本

    #!/usr/bin/env python
    # -*- coding: utf-8 -*-
    
    import os, re
    
    def multi_replace(text, adict):
        rx = re.compile('|'.join(map(re.escape, adict)))
        def xlat(match):
            return adict[match.group(0)]
        return rx.sub(xlat, text)
    
    def batrename(curdir, pairs):
        for fn in os.listdir(curdir):
            newfn = multi_replace(fn, pairs)
            if newfn != fn:
                print("Renames %s to %s in %s." % (fn, newfn, curdir))
                os.rename(os.path.join(curdir, fn), os.path.join(curdir, newfn))
            file = os.path.join(curdir, newfn)
            
            if os.path.isdir(file):
                batrename(file, pairs)
                continue
    
            text = open(file).read()
            newtext = multi_replace(text, pairs)
            if newtext != text:
                print("Renames %s." % (file,))
                open(file, 'w').write(newtext)
    
    if __name__=="__main__":
        while True:
            oldname = raw_input("Old name: ")
            newname = raw_input("New name: ")
            if oldname and newname:
                batrename(os.path.abspath('.'), {oldname:newname})
            else: break
    

      

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  • 原文地址:https://www.cnblogs.com/rhcad/p/2377222.html
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