zoukankan      html  css  js  c++  java
  • hdu2629Identity Card

    Problem Description
    Do you own an ID card?You must have a identity card number in your family's Household Register. From the ID card you can get specific personal information of everyone. The number has 18 bits,the first 17 bits contain special specially meanings:the first 6 bits represent the region you come from,then comes the next 8 bits which stand for your birthday.What do other 4 bits represent?You can Baidu or Google it.
    Here is the codes which represent the region you are in.

    However,in your card,maybe only 33 appears,0000 is replaced by other numbers.
    Here is Samuel's ID number 331004198910120036 can you tell where he is from?The first 2 numbers tell that he is from Zhengjiang Province,number 19891012 is his birthday date (yy/mm/dd).
     
    Input
    Input will contain 2 parts:
    A number n in the first line,n here means there is n test cases. For each of the test cases,there is a string of the ID card number.
     
    Output
    Based on the table output where he is from and when is his birthday. The format you can refer to the Sample Output.
     
    Sample Input
    1 330000198910120036
     
    Sample Output
    He/She is from Zhejiang,and his/her birthday is on 10,12,1989 based on the table.
    #include<stdio.h>
    #include<string.h>
    #include<iostream>
    #include<map>
    using namespace std;
    char a[20],mp[88][15];
    int main()
    {
        int n,y,m,d,dd;
        strcpy(mp[33],"Zhejiang");
        strcpy(mp[82],"Macao");
        strcpy(mp[11],"Beijing");
        strcpy(mp[54],"Tibet");
        strcpy(mp[71],"Taiwan");
        strcpy(mp[21],"Liaoning");
        strcpy(mp[81],"Hong Kong");
        strcpy(mp[31],"Shanghai");
        scanf("%d",&n);
        while(n--)
        {
            scanf("%s",a);
            dd=0; y=0;
            for(int i=0;i<2;i++) dd=dd*10+a[i]-'0';
            for(int i=6;i<=9;i++) y=y*10+a[i]-'0';
            printf("He/She is from %s,and his/her birthday is on ",mp[dd]);
            printf("%c%c,%c%c,%d",a[10],a[11],a[12],a[13],y);
            printf(" based on the table.
    ");
        }
    }
    


     
  • 相关阅读:
    sql 行转列
    wm_concat函数 用法
    PL/SQL如何调试Oracle存储过程
    Oracle&SQLServer中实现跨库查询
    Oracle 中 decode 函数用法
    Oracle中给用户赋予debug权限
    Oracle中的NVL函数
    oracle 触发器 pragma autonomous_transaction
    ORACLE中%TYPE和%ROWTYPE的使用
    A complete example using RAISE_APPLICATION_ERROR : raise_application_error
  • 原文地址:https://www.cnblogs.com/riasky/p/3476575.html
Copyright © 2011-2022 走看看