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  • Search in Rotated Sorted Array II

    Question:

    Follow up for "Search in Rotated Sorted Array":
    What if duplicates are allowed?

    Would this affect the run-time complexity? How and why?

    Write a function to determine if a given target is in the array.

    Solution:

     1 class Solution {
     2 public:
     3     bool search(vector<int>& nums, int target) 
     4     {
     5        int left=0;
     6     int right=nums.size()-1;
     7     if(left==right && nums[left]==target)
     8         return true;
     9     while(left!=right)
    10     {
    11         int mid=(left+right)/2;
    12         if(nums[mid]==target) return true;
    13         if(nums[left]<nums[mid])
    14         {
    15             if(nums[left]<=target && target<=nums[mid])
    16                 right=mid;
    17             else
    18                 left=mid+1;
    19         }
    20         else if(nums[left]>nums[mid])
    21         {
    22             if(nums[mid]<=target && target<=nums[right])
    23                 left=mid+1;
    24             else
    25                 right=mid;
    26         }
    27         else
    28             left++;
    29         if(left==right && nums[left]==target)
    30             return true;
    31     }
    32     return false;  
    33     }
    34 };

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  • 原文地址:https://www.cnblogs.com/riden/p/4631423.html
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