zoukankan      html  css  js  c++  java
  • POJ 1573 (13.10.11)

    Description


    A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are 

    N north (up the page) 
    S south (down the page) 
    E east (to the right on the page) 
    W west (to the left on the page) 

    For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid. 

    Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits. 

    You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around. 

    Input

    There will be one or more grids for robots to navigate. The data for each is in the following form. On the first line are three integers separated by blanks: the number of rows in the grid, the number of columns in the grid, and the number of the column in which the robot enters from the north. The possible entry columns are numbered starting with one at the left. Then come the rows of the direction instructions. Each grid will have at least one and at most 10 rows and columns of instructions. The lines of instructions contain only the characters N, S, E, or W with no blanks. The end of input is indicated by a row containing 0 0 0.

    Output

    For each grid in the input there is one line of output. Either the robot follows a certain number of instructions and exits the grid on any one the four sides or else the robot follows the instructions on a certain number of locations once, and then the instructions on some number of locations repeatedly. The sample input below corresponds to the two grids above and illustrates the two forms of output. The word "step" is always immediately followed by "(s)" whether or not the number before it is 1.

    Sample Input

    3 6 5
    NEESWE
    WWWESS
    SNWWWW
    4 5 1
    SESWE
    EESNW
    NWEEN
    EWSEN
    0 0 0

    Sample Output

    10 step(s) to exit
    3 step(s) before a loop of 8 step(s)

    题意: 不难理解, 我简单说说, 给出r行c列, 然后从第一行的第i个位置开始走

    每个位置有标记E W S N, 分别表示向东, 向西, 向南, 向北

    然后, 有两种情况, 一种能走出去, 一种是陷入死循环


    做法: 每一步都标上是第几步走的就OK了~ 然后按题意模拟~


    AC代码:

    #include<stdio.h>
    
    char str[100][100];
    
    int main() {
        int r, c, in;
        while(scanf("%d %d %d", &r, &c, &in) != EOF) {
            if(r == 0 && c ==0 && in == 0)
                break;
            getchar();
            for(int i = 0; i < r; i++)
                gets(str[i]);
            int tr, tc, loop;
            int step = 0;
            int mark = 1;
            tr = 0; tc = in-1;
    
            while(1) {
                if(str[tr][tc] == 'E') {
                    step++;
                    str[tr][tc] = step + '0';
                    if(tc == c-1)
                        break;
                    else
                        tc = tc + 1;
                }
                else if(str[tr][tc] == 'W') {
                    step++;
                    str[tr][tc] = step + '0';
                    if(tc == 0)
                        break;
                    else
                        tc = tc - 1;
                }
                else if(str[tr][tc] == 'S') {
                    step++;
                    str[tr][tc] = step + '0';
                    if(tr == r-1)
                        break;
                    else
                        tr = tr + 1;
                }
                else if(str[tr][tc] == 'N') {
                    step++;
                    str[tr][tc] = step + '0';
                    if(tr == 0)
                        break;
                    else
                        tr = tr - 1;
                }
                else {
                    mark = 0;
                    loop = str[tr][tc] - '0' - 1;
                    printf("%d step(s) before a loop of %d step(s)
    ", loop, step - loop);
                    break;
                }
            }
            if(mark == 1)
                printf("%d step(s) to exit
    ", step);
        }
        return 0;
    }
  • 相关阅读:
    使用 WebSphere Adapter for SAP Software V7.5 配置 SAP 系统和客户端之间的安全网络通信 (SNC)
    在 ubuntu 12.04 上安装 redmine
    配置nat稳定网络防病毒
    利用 Replication Handler 备份索引
    .NET 4.5对Base Class Library做出改善
    redmine 和 gitolite 的整合
    IBM Power7 服务器 Hypervisor 内存使用情况研究
    Word域代码的显示
    转载:深入分析MFC文档视图
    VIM常用指令
  • 原文地址:https://www.cnblogs.com/riskyer/p/3364657.html
Copyright © 2011-2022 走看看