349. Intersection of Two Arrays

Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2].

Note:

Each element in the result must be unique.

The result can be in any order.

class Solution(object):
    def intersection(self, nums1, nums2):
        """
        :type nums1: List[int]
        :type nums2: List[int]
        :rtype: List[int]
        """
        return list(set(nums1)&set(nums2))

class Solution(object):
    def intersection(self, nums1, nums2):
        """
        :type nums1: List[int]
        :type nums2: List[int]
        :rtype: List[int]
        """
        rlist=[]
        i=j=0
        nums1.sort()
        nums2.sort()
        n=len(nums1)
        m=len(nums2)
        while i<n and j<m:
            if nums1[i]<nums2[j]:
                i+=1
            elif nums1[i]>nums2[j]:
                j+=1
            else:
                if len(rlist)==0 or rlist[-1]!=nums1[i]:
                    rlist.append(nums1[i])
                i+=1
                j+=1
        return rlist