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  • POJ 3254 Corn Fields 状压DP

    水题,记录一下当前是第几行和上一行的状态就好,因为每一行只会受到上一行的限制

    #include <cstdio>
    #include <cstring>
    #include <iostream>
    #include <map>
    #include <set>
    #include <vector>
    #include <string>
    #include <queue>
    #include <deque>
    #include <bitset>
    #include <list>
    #include <cstdlib>
    #include <climits>
    #include <cmath>
    #include <ctime>
    #include <algorithm>
    #include <stack>
    #include <sstream>
    #include <numeric>
    #include <fstream>
    #include <functional>
    
    using namespace std;
    
    #define MP make_pair
    #define PB push_back
    typedef long long LL;
    typedef unsigned long long ULL;
    typedef vector<int> VI;
    typedef pair<int,int> pii;
    const int INF = INT_MAX / 3;
    const double eps = 1e-8;
    const LL LINF = 1e17;
    const double DINF = 1e60;
    const int mod = 1e8;
    const int maxn = 12;
    int n,m,field[maxn],tmp[maxn];
    int f[maxn][1 << 13];
    
    bool ok(int row,int state) {
        if(~field[row] & state) return false;
        int prev = 0,now;
        while(state) {
            now = state & 1;
            if(now == prev && now == 1) return false;
            prev = now;
            state >>= 1;
        }
        return true;
    }
    
    int dfs(int now,int prev) {
        if(now == n) return 1;
        if(~f[now][prev]) return f[now][prev];
        int ret = 0;
        for(int i = 0;i < (1 << 12);i++) if(ok(now,i)) {
            if((i | prev) == prev) {
                ret = (dfs(now + 1,~i & field[now + 1]) + ret) % mod;
            }
        }
        return f[now][prev] = ret;
    }
    
    int main() {
        while(scanf("%d%d",&n,&m) != EOF) {
            memset(field,0,sizeof(field));
            memset(f,-1,sizeof(f));
            for(int i = 0;i < n;i++) {
                for(int j = 0;j < m;j++) {
                    scanf("%d",&tmp[j]);
                }
                for(int j = m - 1;j >= 0;j--) {
                    field[i] = (field[i] << 1) | tmp[j];
                }
            }
            int ans = dfs(0,(1 << 12) - 1);
            printf("%d
    ",ans);
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/rolight/p/3904659.html
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