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  • POJ 1379 Run Away 模拟退火

    一开始写了一发很快的,发现一会能过一会不能,貌似有点悬,毕竟是随机算法。

    后来重写了一发迭代5遍的,基本上把把AC了= =

    模拟退火果然是一种不是很靠谱的算法。

    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #include <cstdlib>
    #include <ctime>
    
    using namespace std;
    const int maxn = 1005;
    const double eps = 1e-8;
    const double r = 0.99;
    const int dx[] = { 0, 0, 1, -1, 1, -1, 1, -1 };
    const int dy[] = { 1, -1, 0, 0, 1, -1, -1, 1 };
    
    int px[maxn], py[maxn];
    int X, Y, M;
    
    double sq(double x) {
    	return x * x;
    }
    
    double dis(double x, double y) {
    	double ret = 1e90;
    	for (int i = 0; i < M; i++) {
    		ret = min(ret, sqrt(sq(x - px[i]) + sq(y - py[i])));
    	}
    	return ret;
    }
    
    double solve(double &x, double &y) {
    	double nowdis = dis(x, y);
    	double step = max(X, Y);
    	while (step > eps) {
    		for (int i = 0; i < 8; i++) {
    			double nx = x + dx[i] * step,
    				ny = y + dy[i] * step,
    				ndis = dis(nx, ny);
    			if (nx > X || nx < 0 || ny > Y || ny < 0) continue;
    			if (ndis > nowdis) {
    				x = nx; y = ny; nowdis = ndis;
    			}
    		}
    		step *= r;
    	}
    	return nowdis;
    }
    
    int main() {
    	int T; scanf("%d", &T);
    	srand(time(NULL));
    	while (T--) {
    		scanf("%d%d%d", &X, &Y, &M);
    		for (int i = 0; i < M; i++) scanf("%d%d", &px[i], &py[i]);
    		double nowdis = 0, x, y;
    		for (int i = 0; i < 5; i++) {
    			double tx = rand() % (X), ty = rand() % (Y);
    			double ret = solve(tx, ty);
    			if (ret > nowdis) {
    				nowdis = ret;
    				x = tx; y = ty;
    			}
    		}
    		printf("The safest point is (%.1f, %.1f).
    ",
    			x, y);
    	}
    	return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/rolight/p/3973839.html
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