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  • BZOJ 1012

    题链

    一道线段树。看代码吧

    #pragma GCC optimize("-O2")
    #include<bits/stdc++.h>
    //#define getchar nc
    #define sight(c) ('0'<=c&&c<='9')
    #define siight(c) ('A'<=c&&c<='Z') 
    #define LL long long
    #define deg printf
    #define dput put
    #define dputc putchar
    #define db double 
    #define N 200007
    #define eho(x) for(int i=head[x];i;i=net[i])
    inline char nc(){
        static char buf[1000000],*p1=buf,*p2=buf;
        return p1==p2&&(p2=(p1=buf)+fread(buf,1,1000000,stdin),p1==p2)?EOF:*p1++;
    }
    inline void read(int &x){
        static char c;
        for (c=getchar();!sight(c);c=getchar());
        for (x=0;sight(c);c=getchar())x=x*10+c-48;
    }
    inline void readC(char &x){
        for (x=getchar();!siight(x);x=getchar());
    }
    void write(int x){if (x<10) {putchar('0'+x); return;} write(x/10); putchar('0'+x%10);}
    inline void writeln(int x){ if (x<0) putchar('-'),x*=-1; write(x); putchar('
    '); }
    using namespace std;
    int p[N<<2|N],n,mo,x,lastans,tot;
    #define Mid (l+r>>1)
    char ch;
    void change(int node,int l,int r,int op,int dal){
        if (l==r) { p[node]=dal;return;}
        if (op<=Mid) change(node<<1,l,Mid,op,dal);
        else change(node<<1|1,Mid+1,r,op,dal);
        p[node]=max(p[node<<1],p[node<<1|1]);
    }
    int query(int node,int l,int r,int L,int R){
        if (L<=l&&r<=R) return p[node];
        if (R<=Mid) return query(node<<1,l,Mid,L,R);
        if (L> Mid) return query(node<<1|1,Mid+1,r,L,R);
        return max(query(node<<1,l,Mid,L,Mid),query(node<<1|1,Mid+1,r,Mid+1,R));
    }
    int main () {
    //    freopen("1.in","r",stdin);
        read(n); read(mo);
        while (n--) {
            readC(ch); read(x);
            if (ch=='A') {
                x=(1ll*x+lastans)%mo,change(1,1,N,++tot,x);
            } else {
                lastans=query(1,1,N,tot-x+1,tot),
                writeln(lastans);
            }
        } return 0;
    }
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  • 原文地址:https://www.cnblogs.com/rrsb/p/8416270.html
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