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  • python学习笔记—— 函数

    〈p>读取远程页面

    from urllib import urlretrieve
    
    def printFile(url):
        f = open(url)
        for line in f:
            if line.strip():
                print line
        f.close()
    
    def loadFile(url=r'http://www.idkin.com/contact.html', process=printFile):
        try:
            fileName = urlretrieve(url,'tmp.html')[0]
            print(fileName)
        except BaseException, e:
            print(str(e))
        if fileName:
            process(fileName)
    
    if __name__ == "__main__":
        loadFile()
    
    #urlretrieve的返回值是一个tuple, 第一个元素就是目标文件名
    #如果urlretrieve仅获取一个参数,返回值的第一个元素就是产生的临时文件名
    

    filter函数,类似javascript1.7的Array#filter。filter函数的功能相当于过滤器。调用一个布尔函数fn来迭代遍历每个seq中的元素;返回一个使fn返回值为true的元素的序列。

    from random import randint
    def filter(fn,arr):
        ret = [];
        for i in arr:
            if fn(i):
                ret.append(i)
        return ret;
    arr = [1,2,3,4,5,6];
    print filter(lambda n:n%2,arr)
    

    map函数,类似javascript1.7的Array#map。map函数func作用于给定序列的每个元素,并用一个列表来提供返回值。

    from random import randint
    def map(fn,arr):
        ret = [];
        for i in arr:
            ret.append(fn(i))
        return ret;
    arr = [1,2,3,4,5,6];
    print map(lambda n:n+10,arr)
    

    我们也可以用并归的思想实现此迭代器:

    def rmap ( fun, list ):
        if list == []:
            return []
        else:
            return [fun( list[0] )] + rmap( fun, list[1:] )
    

    reduce函数,类似javascript1.7的Array#reduce。fn为二元函数,将fn作用于seq序列的元素,每次携带一对(先前的结果以及下一个序列的元素),连续的将现有的结果和下一个值作用在获得的随后的结果上,最后减少我们的序列为一个单一的返回值。

    from random import randint
    def reduce(fn,seq,initial=None): 
        lseq = list(seq) 
        if initial is None: 
            res = lseq.pop(0) 
        else: 
            res = initial 
        for i in lseq: 
            res = fn(res,i) 
        return res
    arr = [1,2,3,4,5,6];
    print reduce(lambda a,b:a+b,arr)
    

    追踪闭包词法的变量

    output = 'int %r id=%#0x val=%d'
    w = x = y =z  =1
    
    def f1():
        x = y = z = 2
        
    def f2():
        y = z = 3
        
        def f3():
            z = 4
            print output %('w', id(w),w)
            print output %('x', id(x),x)
            print output %('y', id(y),y)
            print output %('z', id(z),z)
            
            clo = f3.func_closure
            if clo:
                print "f3 closure vars: ",[str(c) for c in clo]
            else:
                print "no f3 closure vars"
                
        f3()
        clo = f2.func_closure
        if clo:
            print "f2 closure vars: ",[str(c) for c in clo]
        else:
            print "no f2 closure vars"
    f2()
        
    clo = f1.func_closure
    if clo:
        print "f1 closure vars: ",[str(c) for c in clo]
    else:
        print "no f1 closure vars"
    f1()
       

    打印日志

    
    # coding='utf-8'
    from time import time
    
    def logged(when):
        def log(f,*args,**kargs):
            print '''Called:
            function:%s
            args:%r
            kargs:%r''' % (f,args,kargs)
        def pre_logged(f):
            def wrapper(*args,**kargs):
                log(f,*args,**kargs)
                return f(*args,**kargs)
            return wrapper
    
        def post_logged(f):
            def wrapper(*args,**kargs):
                now=time()
                try:
                    return f(*args,**kargs)
                finally:
                    log(f,*args,**kargs)
                    print "time delta: %s" %(time()-now)
            return wrapper
    
        try:
            return {"pre":pre_logged,"post":post_logged}[when]
        except KeyError, e:
            raise ValueError(e),'must be "pre" or "post"'
    
    @logged("post")
    def hello(name):
        print "Hello,",name
    
    hello("World")
    
    

    生成器

    
    # coding='utf-8'
    def counter(start_at=10):
        count = start_at
        while(True):
            val = (yield count)
            if(val is not None):
                count = val
            else:
                count += 1
                if(count == 10):
                    break
    
    for i in counter(3):
       print i
    
    
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  • 原文地址:https://www.cnblogs.com/rubylouvre/p/2090088.html
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