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  • switch-case的选择用法

    企业发放的奖金根据利润提成。利润I低于或等于100000元的,奖金可提0.1;利润高于100000元,低于200000(100000<I<=200000)时,低于100000元的部分按10%提成,高于100000元的部分,可提成7.5%;200000<I<=400000时,低于200000元的部分仍按上述办法提成(下同)。高于200000元的部分按5%提成;400000<I<=600000元时,高于400000元的部分按3%提成;600000<I<=1000000时,高于600000元的部分按1.5%提成;I>1000000时,超过1000000元的部分按1%提成。从键盘输入当月利润I,求应发奖金总数。
    要求:
    (1)用if语句编程序;
    (2)用switch语句编程序。

     1 include<iostream>
     2 using namespace std;
     3 int main()
     4 {
     5     int opt;
     6     float profit;
     7     cout<<"please choose the mode: 1[if]/2[switch] 
    ";
     8     cin>>opt;
     9     switch(opt)
    10     {
    11     case 1:
    12         {
    13             cout<<"MODE "if" chosen
    ";
    14             cout<<"please enter monthly profit($):";
    15             cin>>profit;
    16             float sum;
    17             if(profit<=1e5)
    18             {sum=profit*0.1;}
    19             else if(profit<=2e5)
    20             {sum=1e5*0.1+(profit-1e5)*0.075;}
    21             else if(profit<=4e5)
    22             {sum=1e5*0.1+1e5*0.075+(profit-2e5)*0.05;}
    23             else if(profit<=6e5)
    24             {sum=1e5*0.1+1e5*0.075+2e5*0.05+(profit-4e5)*0.03;}
    25             else if(profit<=1e6)
    26             {sum=1e5*0.1+1e5*0.075+2e5*0.05+2e5*0.03+(profit-6e5)*0.015;}
    27             else
    28             {sum=1e5*0.1+1e5*0.075+2e5*0.05+2e5*0.03+4e5*0.015+(profit-1e6)*0.01;}
    29             cout<<"your bonus is: "<<sum<<'$'<<endl;
    30         };break;
    31     case 2:
    32         {
    33             cout<<"MODE "switch" chosen
    ";
    34             cout<<"please enter monthly profit($):";
    35             cin>>profit;
    36             float sum;
    37             switch(int(profit/1e5))
    38             {
    39             case 0:
    40                 {sum=profit*0.1;};break;
    41             case 1:
    42                 {sum=1e5*0.1+(profit-1e5)*0.075;};break;
    43             case 2:
    44                 {sum=1e5*0.1+1e5*0.075+(profit-2e5)*0.05;};
    45             case 3:
    46                 break;
    47             case 4:
    48             case 5:
    49                 {sum=1e5*0.1+1e5*0.075+2e5*0.05+(profit-4e5)*0.03;};break;
    50             case 6:                
    51             case 7:
    52             case 8:
    53             case 9:
    54                 {sum=1e5*0.1+1e5*0.075+2e5*0.05+2e5*0.03+(profit-6e5)*0.015;};break;
    55             default :
    56                 {sum=1e5*0.1+1e5*0.075+2e5*0.05+2e5*0.03+4e5*0.015+(profit-1e6)*0.01;};break;
    57             }
    58             cout<<"your bonus is: "<<sum<<'$'<<endl;
    59         };break;
    60     }
    61         
    62        return 0;
    63 }   

     

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  • 原文地址:https://www.cnblogs.com/runsdeep/p/11146309.html
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