zoukankan      html  css  js  c++  java
  • POJ 3417 Network

    Time Limit: 2000MS   Memory Limit: 65536K
    Total Submissions: 5277   Accepted: 1513

    Description

    Yixght is a manager of the company called SzqNetwork(SN). Now she's very worried because she has just received a bad news which denotes that DxtNetwork(DN), the SN's business rival, intents to attack the network of SN. More unfortunately, the original network of SN is so weak that we can just treat it as a tree. Formally, there are N nodes in SN's network, N-1 bidirectional channels to connect the nodes, and there always exists a route from any node to another. In order to protect the network from the attack, Yixght builds M new bidirectional channels between some of the nodes.

    As the DN's best hacker, you can exactly destory two channels, one in the original network and the other among the M new channels. Now your higher-up wants to know how many ways you can divide the network of SN into at least two parts.

    Input

    The first line of the input file contains two integers: N (1 ≤ N ≤ 100 000), M (1 ≤ M ≤ 100 000) — the number of the nodes and the number of the new channels.

    Following N-1 lines represent the channels in the original network of SN, each pair (a,b) denote that there is a channel between node a and node b.

    Following M lines represent the new channels in the network, each pair (a,b) denote that a new channel between node a and node b is added to the network of SN.

    Output

    Output a single integer — the number of ways to divide the network into at least two parts.

    Sample Input

    4 1
    1 2
    2 3
    1 4
    3 4
    

    Sample Output

    3

    Source

     
    树剖+树上差分+树形dp
  • 相关阅读:
    51nod 1117 聪明的木匠:哈夫曼树
    51nod 1010 只包含因子2 3 5的数
    51nod 2636 卡车加油
    51nod 2989 组合数
    51nod 2652 阶乘0的数量 V2
    51nod 1103 N的倍数
    51nod 2489 小b和灯泡
    51nod 1003 阶乘后面0的数量
    51nod 2122 分解质因数
    javascript中的setter和getter
  • 原文地址:https://www.cnblogs.com/ruojisun/p/7597818.html
Copyright © 2011-2022 走看看