给你一堆文件名,排序后按列优先的方式左对齐输出。
假设最长文件名长度是M,那么每一列都要有M+2字符,最后一列有M字符。
inmanip真NB。。orz
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <vector>
#include <string>
#include <cstring>
#include <iomanip>
#include <algorithm>
using namespace std;
const int MAX = 60;
int main()
{
int n;
while(scanf("%d", &n) != EOF)
{
vector<string> ss;
int maxlen = 0;
string s;
for (int i = 0; i < n; i++)
{
cin >> s;
maxlen = max(maxlen, (int)s.size());
ss.push_back(s);
}
sort(ss.begin(), ss.end());
int cols = (MAX+2) / (maxlen+2);
int rows = (n-1) / cols + 1; //巧妙
//cout << cols << " " << rows << endl;
printf("------------------------------------------------------------
");
cout << setiosflags(ios :: left);
for (int j = 0; j < rows; j++)
{
for (int i = 0; i < n; i++)
if (i % rows == j) //SB的我改了好久
cout << setw(maxlen + 2) << ss[i];
cout << endl;
}
}
}