1.输入一个年份,判断是不是闰年(能被4整除但不能被100整除,或者能被400整除)
import java.util.Scanner; public class first { public static void main(String[] args) { System.out.println("请输入一个年份"); Scanner sc = new Scanner(System.in); int year = sc.nextInt(); if ((year % 4 == 0 && year % 100 != 00) || (year % 400 == 0)) { System.out.println(year + "是一个闰年"); } else { System.out.println(year + "是一个平年"); } } }
2.输入一个4位会员卡号,如果百位数字是3的倍数,就输出是幸运会员,否则就输出不是.
import java.util.Scanner; public class first { public static void main(String[] args) { System.out.println("请输入会员卡号"); Scanner sc = new Scanner(System.in); int id = sc.nextInt(); if (id % 1000 / 100 % 3 == 0) { System.out.println("幸运会员"); } else { System.out.println("不是"); } } }
3.已知函数,输入x的值,输出对应的y的值.
x + 3 ( x > 0 )
y = 0 ( x = 0 )
x*2 –1 ( x < 0 )
import java.util.Scanner; public class first { public static void main(String[] args) { System.out.println("请输入x的值"); Scanner sc = new Scanner(System.in); int x = sc.nextInt(); int y; if (x>0) { y=x+3; System.out.println("y的值为:"+y); } else if (x==0){ y=0; System.out.println("y的值为:"+y); }else if (x<0){ y=x*2-1; System.out.println("y的值为:"+y); } } }
4.输入三个数,判断能否构成三角形(任意两边之和大于第三边)
import java.util.Scanner; public class first { public static void main(String[] args) { System.out.println("三角形的三个边长"); Scanner sc = new Scanner(System.in); int a = sc.nextInt(); int b = sc.nextInt(); int c = sc.nextInt(); if ((a + b) > c && (a + c) > b && (b + c) > a) { System.out.println("可以构成三角形"); } System.out.println("不可以构成三角型"); } }