UVA 210 Concurrency Simulator

https://vjudge.net/problem/UVA-210

题目

模拟并行计算机……

题解

错了一次，把“Any instruction currently being executed when the time quantum expires will be allowed to complete.”理解成了这条指令超出quantum剩余时间的部分在下一次执行……实际上是这次执行完……多了个变量，还好改得不多

AC代码

#include<bits/stdc++.h>
#define REP(i,x,y) for(register int i=x; i<y; i++)
#define REPE(i,x,y) for(register int i=x; i<=y; i++)
#ifdef LOCAL
#define DBG(x, ...) printf(x, ##__VA_ARGS__)
#else
#define DBG(x, ...) (void)(0)
#endif
using namespace std;

int t[5];
int quantum;
struct node {
	int op;
	char var;
	int imm;
};
struct prog {
	vector<node> statement;
	int nowi;
};
vector<prog> exe;
queue<int> block;
deque<int> ready;
int vars[26];
bool locked=false;

int main() {
	int kase;
	scanf("%d", &kase);
	REP(_, 0 ,kase) {
	
	if(_) putchar('
');
	memset(vars, 0, sizeof vars);
	int T;
	scanf("%d", &T);
	REP(i,0,5) scanf("%d", &t[i]);
	scanf("%d", &quantum);
	exe = vector<prog>(T);
	REP(i,0,T) {
		exe[i].nowi=0;
		while(1) {
			node x;
			char k[17];
			scanf("%s", k);
			if(k[1]==0) {
				x.op=0;
				scanf("%*s%d", &x.imm);
				x.var=k[0];
			} else {
				switch(k[2]) {
					case 'i':
						x.op=1;
						scanf("%s", k);
						x.var=k[0];
						break;
					case 'c':
						x.op=2;
						break;
					case 'l':
						x.op=3;
						break;
					case 'd':
						x.op=4;
						exe[i].statement.push_back(x);
						goto _nxt;
						break;
				}
			}
			exe[i].statement.push_back(x);
		}
		_nxt:
		ready.push_back(i);
	}
	locked = false;
	while(!ready.empty()) {
		int nowid=ready.front(); ready.pop_front();
		int q=quantum;
		while(1) {
			int &i=exe[nowid].nowi;
			int nowop=exe[nowid].statement[i].op;
			node &now = exe[nowid].statement[i];
			int tnowop=t[nowop];
			
			if(q>0) {
//				DBG("```%d - %d~%d
", nowid+1, i, j);
				switch(nowop) {
					case 0:
						vars[now.var-'a']=now.imm;
//						DBG("###%c = %d
", now.var, now.imm);
						break;
					case 1:
						printf("%d: %d
", nowid+1, vars[now.var-'a']);
						break;
					case 2:
						if(locked) {
							block.push(nowid);
							goto _gonxt;
							break;
						} else {
							locked = true;
							break;
						}
					case 3:
						locked = false;
						if(!block.empty()) {
							int bf = block.front(); block.pop();
							ready.push_front(bf);
						}
						break;
					case 4:
						goto _gonxt;
						break;
				}
				q-=tnowop; i++;
			} else {
				q=0;
				ready.push_back(nowid);
				break;
			}
		}
		_gonxt:;
	}
	
	}
	return 0;
}

 还是乱……以后尝试分开写