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  • 「题目代码」P1029~P1033(Java)

    1029 C基础-求解方程

    import java.util.*;
    import java.io.*;
    import java.math.BigInteger;
    
    public class Main
    {
        public static void main(String args[])
        {
            for(int i=100;i<=999;++i)
            {// 这特么不需要排除相同项
                int j=1333-i; if(/* i>j || */j<100 || j>=1000) continue;
                int ig=i%10,is=(i/10)%10,ib=i/100,
                    jg=j%10,js=(j/10)%10,jb=j/100;
    
                if(ig==jb && ib==jg && is==js)
                {
                    System.out.println(i+"+"+j+"="+1333);
                }
            }
        }
    }

    1030 C基础-选择半径

    import java.util.*;
    import java.io.*;
    import java.math.BigInteger;
    
    public class Main
    {
        public static void main(String args[])
        {
            Scanner cin=new Scanner(System.in);
            for(int i=1;i<=10;++i)
            {
                double s=i*3.14159*i;
                if(s>=40.0 && s<=90.0)
                {
                    System.out.printf("r=%d area=%.2f
    ",i,s);
                }
            }
        }
    }

    1031 C基础-选择排序

    /* Insertion Sort - P1031
     * The algorithm divides the input list into two parts: the sublist of items    
     * already sorted, which is built up from left to right at the front (left) of
     * the list, and the sublist of items remaining to be sorted that occupy the
     * rest of the list. Initially, the sorted sublist is empty and the unsorted
     * sublist is the entire input list. The algorithm proceeds by finding the
     * smallest (or largest, depending on sorting order) element in the unsorted
     * sublist, exchanging (swapping) it with the leftmost unsorted element
     * (putting it in sorted order), and moving the sublist boundaries one element
     * to the right.
     */
    import java.util.*;
    import java.io.*;
    import java.math.BigInteger;
    
    public class Main
    {
        public static void main(String args[])
        {
            Scanner cin=new Scanner(System.in);
            int[] arr=new int[15];
            for(int i=1;i<=10;++i)
            {
                arr[i]=cin.nextInt();
            }
            for(int i=1;i<=10;++i)
            {
                int minId=i;
                for(int j=i;j<=10;++j)
                    if(arr[minId]>arr[j])
                        minId=j;
                swap(arr,minId,i);
            }
            for(int i=1;i<=10;++i)
                System.out.println(arr[i]);
        }
        // a mainstream implementation due to limitation of Java itself.
        public static void swap(int[] arr, int a, int b) {  
            int temp = arr[a];  
            arr[a] = arr[b];  
            arr[b] = temp;  
        }
    }

    1032 C基础-局部求和

    import java.util.*;
    import java.io.*;
    import java.math.BigInteger;
    
    public class Main
    {
        public static void main(String args[])
        {
            Scanner cin=new Scanner(System.in);
            int[] arr=new int[25];
            for(int i=1;i<=20;++i)
            {
                arr[i]=cin.nextInt();
            }
            for(int i=1;i<=20;++i)
            {
                for(int j=1;j<=20;++j)
                {
                    if(i==j) continue;
                    if(arr[i]%arr[j]==0) {System.out.println(arr[i]); break;}
                }
            }
        }
    }

    1033 C基础-对角线和

    import java.util.*;
    import java.io.*;
    import java.math.BigInteger;
    
    public class Main
    {
        public static void main(String args[])
        {
            Scanner cin=new Scanner(System.in);
            int[][] arr=new int[5][5];
            for(int i=1;i<=3;++i)
            {
                for(int j=1;j<=3;++j)
                    arr[i][j]=cin.nextInt();
            }
            System.out.println((int)(arr[1][1]+arr[2][2]+arr[3][3]));
        }
    }
    如非注明,原创内容遵循GFDLv1.3发布;其中的代码遵循GPLv3发布。
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  • 原文地址:https://www.cnblogs.com/samhx/p/9652072.html
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