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  • Node.js之Path模块

    Node.js path 模块提供了一些用于处理文件路径的小工具,我们可以通过以下方式引入该模块:

    const path = require("path")

    方法

    1、path.join([path1][, path2][, ...]):

    const path = require("path");
    
    console.log(path.join(__dirname + "/index.html" + "/abc" + ".../" + "123")); // G:work
    ode
    ode1index.htmlabc...123
    console.log(path.join(__dirname + "/index.html" + "/abc" + "/.../" + "123")); // G:work
    ode
    ode1index.htmlabc...123
    console.log(path.join(__dirname + "/index.html" + "/abc" + "/../" + "123")); // G:work
    ode
    ode1index.html123
    console.log(path.join(__dirname + "/index.html" + "/abc" + "../" + "123")); // G:work
    ode
    ode1index.htmlabc..123
    console.log(path.join(__dirname + "/index.html" + "/abc" + "/./" + "123")); // G:work
    ode
    ode1index.htmlabc123
    console.log(path.join(__dirname + "/index.html" + "/abc" + "./" + "123")); // G:work
    ode
    ode1index.htmlabc.123
     

    拼接方式:

    1)先连接,连接时去掉“”等特殊字符;

    2)连接后处理"/../"和"/./"情况。

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  • 原文地址:https://www.cnblogs.com/samve/p/14208970.html
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