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  • Search a 2D Matrix

    Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

    • Integers in each row are sorted from left to right.
    • The first integer of each row is greater than the last integer of the previous row.

    For example,

    Consider the following matrix:

    [
      [1,   3,  5,  7],
      [10, 11, 16, 20],
      [23, 30, 34, 50]
    ]
    

    Given target = 3, return true.

     1 class Solution {
     2 public:
     3     bool searchMatrix(vector<vector<int>>& matrix, int target) {
     4         if(matrix.size() == 0){
     5             return false;
     6         }
     7         if(matrix[0].size() == 0){
     8             return false;
     9         }
    10         
    11         int rowNumber = 0;
    12         int colNumber = matrix[0].size()-1;
    13         
    14         while(rowNumber < matrix.size() && colNumber >= 0){
    15             
    16             if(matrix[rowNumber][colNumber] > target){
    17                 colNumber--;
    18             }else if(matrix[rowNumber][colNumber] < target){
    19                 rowNumber++;
    20             }else{
    21                 return true;
    22             }
    23         }
    24         return false;
    25     }
    26 };
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  • 原文地址:https://www.cnblogs.com/sankexin/p/5865957.html
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