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  • 82. Remove Duplicates from Sorted List II

    Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

    For example,
    Given 1->2->3->3->4->4->5, return 1->2->5.
    Given 1->1->1->2->3, return 2->3.

     1 /**
     2  * Definition for singly-linked list.
     3  * struct ListNode {
     4  *     int val;
     5  *     ListNode *next;
     6  *     ListNode(int x) : val(x), next(NULL) {}
     7  * };
     8  */
     9 class Solution {
    10 public:
    11     ListNode* deleteDuplicates(ListNode* head) {
    12         if(!head){
    13             return head;
    14         }
    15         
    16         ListNode* newHead = new ListNode(-1);
    17         newHead->next = head;
    18         
    19         ListNode* prev = newHead;
    20         ListNode* p = head;
    21         
    22         while(p && p->next){
    23             
    24             if(p->val != p->next->val){
    25                 prev = p;
    26                 p = p->next;
    27             }else{
    28                 int val = p->val;
    29                 ListNode* n = p->next->next;
    30                 while(n){
    31                     if(n->val != val){
    32                         break;
    33                     }
    34                     n = n->next;
    35                 }
    36                 prev->next = n;
    37                 p = n;
    38             }
    39         }
    40         return newHead->next;
    41     }
    42 };
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  • 原文地址:https://www.cnblogs.com/sankexin/p/5866699.html
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