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  • 64. Minimum Path Sum

    Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

    Note: You can only move either down or right at any point in time.

     1 class Solution {
     2 public:
     3     int minPathSum(vector<vector<int>>& grid) {
     4         if(grid.size() == 0 || grid[0].size() == 0){
     5             return 0;
     6         }
     7         
     8         int row = grid.size();
     9         int col = grid[0].size();
    10         
    11         int dp[row][col];
    12         
    13         dp[0][0] = grid[0][0];
    14         
    15         for(int i = 1; i < row; i++){
    16             dp[i][0] = dp[i-1][0] + grid[i][0];
    17         }
    18         
    19         for(int j = 1; j < col; j++){
    20             dp[0][j] = dp[0][j-1] + grid[0][j];
    21         }
    22         
    23         for(int i = 1; i < row; i++){
    24             for(int j =1; j < col; j++){
    25                 dp[i][j] = min(dp[i-1][j] , dp[i][j-1]) + grid[i][j];
    26             }
    27         }
    28         return dp[row-1][col-1];
    29     }
    30 };
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  • 原文地址:https://www.cnblogs.com/sankexin/p/5874651.html
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