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  • 通过HashSet达到对象集去重的实现(jdk1.8)

    通过HashSet达到对象集去重的实现(jdk1.8)

    public class Contract {
    
        private String contractId;
        private String contractName;
    
        private Date begin;
        private Date end;
    
        @Override
        public boolean equals(Object o) {
            if (this == o) return true;
            if (o == null || getClass() != o.getClass()) return false;
            Contract contract = (Contract) o;
            //自己的判断条件是时间段重合的算做同一个对象
            return false;
        }
    
        @Override
        public int hashCode() {
        	//通过Objects类提供的hash方法
            int hash = Objects.hash(contractId, contractName);
            return hash;
        }
    
    public class Test {
    
        public static void main(String[] args) {
            Calendar calendar = Calendar.getInstance();
            calendar.setTime(new Date());
    
            Contract c1 = new Contract();
            c1.setContractName("c");
            c1.setContractId("1");
    
            c1.setBegin(calendar.getTime());
            calendar.set(Calendar.DAY_OF_MONTH,calendar.get(Calendar.DAY_OF_MONTH)+1);
            c1.setEnd(calendar.getTime());
            /*                  */
            Contract c2 = new Contract();
            c2.setContractName("c");
            c2.setContractId("1");
    
            calendar.setTime(new Date());
            c2.setBegin(calendar.getTime());
            calendar.set(Calendar.DAY_OF_MONTH,calendar.get(Calendar.DAY_OF_MONTH)+2);
            c2.setEnd(calendar.getTime());
    
            HashSet<Contract> set = new HashSet<>();
            set.add(c1);
            set.add(c2);
            System.out.println(set.size());
        }
    }
    
    1.HashSet内部维护类了一个HashMap,可以看到默认的构造方法其实就是实例化了一个hashMap
     private transient HashMap<E,Object> map;
    
        // Dummy value to associate with an Object in the backing Map
        private static final Object PRESENT = new Object();
    
        /**
         * Constructs a new, empty set; the backing <tt>HashMap</tt> instance has
         * default initial capacity (16) and load factor (0.75).
         */
        public HashSet() {
            map = new HashMap<>();
        }
    
        /**
         * Constructs a new set containing the elements in the specified
         * collection.  The <tt>HashMap</tt> is created with default load factor
         * (0.75) and an initial capacity sufficient to contain the elements in
         * the specified collection.
         *
         * @param c the collection whose elements are to be placed into this set
         * @throws NullPointerException if the specified collection is null
         */
        public HashSet(Collection<? extends E> c) {
            map = new HashMap<>(Math.max((int) (c.size()/.75f) + 1, 16));
            addAll(c);
        }
    
    2.在添加对象的时候判断了对象是否的hashCode是否相等,如果相等需要进一步判断对象的equals方法
     final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
                       boolean evict) {
            Node<K,V>[] tab; Node<K,V> p; int n, i;
            if ((tab = table) == null || (n = tab.length) == 0)
                n = (tab = resize()).length;
            if ((p = tab[i = (n - 1) & hash]) == null)
                tab[i] = newNode(hash, key, value, null);
            else {
                Node<K,V> e; K k;
                if (p.hash == hash &&
                    ((k = p.key) == key || (key != null && key.equals(k))))
                    e = p;
                else if (p instanceof TreeNode)
                    e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
                else {
                    for (int binCount = 0; ; ++binCount) {
                        if ((e = p.next) == null) {
                            p.next = newNode(hash, key, value, null);
                            if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
                                treeifyBin(tab, hash);
                            break;
                        }
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k))))
                            break;
                        p = e;
                    }
                }
                if (e != null) { // existing mapping for key
                    V oldValue = e.value;
                    if (!onlyIfAbsent || oldValue == null)
                        e.value = value;
                    afterNodeAccess(e);
                    return oldValue;
                }
            }
            ++modCount;
            if (++size > threshold)
                resize();
            afterNodeInsertion(evict);
            return null;
        }
    
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  • 原文地址:https://www.cnblogs.com/sansamh/p/9025030.html
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