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  • uva 804WAWAWA--不想看了以后再说

    #include <vector>
    #include <cstdio>
    #include <cstring>
    using namespace std;
    int tokens[105];
    vector<int> in[105], out[105];
    int NP, NT, NF;
    int solve()
    {
        int count = 0, tran_i;
        for (tran_i = 0;tran_i < NT;tran_i++)
        {
            int flag = 0;
            for (int i = in[tran_i].size() - 1;i >= 0;i--)
            {
                if (tokens[in[tran_i][i]] > 0)tokens[in[tran_i][i]]--;
                else {
                    for (int j = in[tran_i].size() - 1;j > i;j--)
                        tokens[in[tran_i][j]]++;
                    flag = 1;
                    break;
                }
            }
            if (flag == 0)
            {
                for (int i = out[tran_i].size() - 1;i >= 0;i--)
                    tokens[out[tran_i][i]]++;
                tran_i = -1;
                if (++count >= NF)return 0;
            }
        }
        return count;
    
    }
    void read()
    {
        int kase = 0;
        while (scanf("%d", &NP) == 1)
        {
            if (NP == 0)return;
            memset(tokens, 0, sizeof(tokens));
            for (int i = 0;i < NP;i++)
                scanf("%d", tokens + i);
            scanf("%d", &NT);
            for (int i = 0;i < NT;i++)
                in[i].clear(), out[i].clear();
            for (int i = 0;i < NT;i++)
            {
                int t;
                scanf("%d", &t);
                while (t)
                {
                    if (t < 0)in[i].push_back(-t - 1);//看别人ac的代码,是把同一个输入库或者输出库统一,鄙人这种方法可能对大量重复数据比较吃力
                    else out[i].push_back(t - 1);
                    scanf("%d", &t);
                }
            }
            scanf("%d", &NF);
            //printf("Case %d: ", ++kase);
            int c = solve();
            if (c == 0)printf("Case %d: still live after %d transitions
    ", ++kase, NF);
            else printf("Case %d: dead after %d transitions
    ", ++kase, c);
            printf("Places with tokens:");
            for (int i = 0;i < NP;i++)
                if (tokens[i])printf(" %d (%d)", i + 1, tokens[i]);
            printf("
    
    ");
        }
    }
    int main(void)
    {
        read();
        return 0;
    }
    //贴下别人的码
    #include<cstdio>
    #include<cstring>
    #include<vector>
    using namespace std;
    const int maxn = 105;
    int p, t, np[maxn], lim;
    struct petri {
        int ip, op, i[maxn], o[maxn], in[maxn], out[maxn];
    } pet[maxn];
    int main() {
        int tt = 0;
        while (scanf("%d", &p), p) {
            memset(pet, 0, sizeof(pet));
            for (int i = 1;i <= p;++i) scanf("%d", &np[i]);
            scanf("%d", &t);
            for (int i = 1;i <= t;++i) {
                int k;
                while (scanf("%d", &k), k) {
                    if (k<0) ++pet[i].in[-k];
                    else ++pet[i].out[k];
                }
                for (int j = 1;j <= p;++j) {
                    if (pet[i].in[j]) pet[i].i[++pet[i].ip] = j;
                    if (pet[i].out[j]) pet[i].o[++pet[i].op] = j;
                }
            }
            scanf("%d", &lim);
            int cnt = 0;
            for (int i = 1;i <= t;++i) {
                bool flag = true;
                petri &k = pet[i];
                for (int j = 1;j <= k.ip;++j)
                    if (np[k.i[j]]<k.in[k.i[j]]) { flag = false;break; }
                if (!flag) continue;
                for (int j = 1;j <= k.ip;++j) np[k.i[j]] -= k.in[k.i[j]];
                for (int j = 1;j <= k.op;++j) np[k.o[j]] += k.out[k.o[j]];
                i = 0;
                if (++cnt >= lim) break;
            }
            if (cnt >= lim) printf("Case %d: still live after %d transitions
    ", ++tt, lim);
            else printf("Case %d: dead after %d transitions
    ", ++tt, cnt);
            printf("Places with tokens:");
            for (int i = 1;i <= p;++i) if (np[i]) printf(" %d (%d)", i, np[i]);
            printf("
    
    ");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/schsb/p/7898779.html
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