SELECT t3.college_code FROM ( SELECT t1.college_code, IF ( find_in_set( t1.parent_org_code, @pids ) > 0, @pids := concat( @pids, ',', t1.college_code ), 0 ) AS ischild FROM ( SELECT college_code, parent_org_code FROM t_college t WHERE t.STATUS = 1 ORDER BY parent_org_code, college_code ) t1, ( SELECT @pids := '22300' college_code ) t2 ) t3 WHERE t3.ischild != 0
表结构: t_college: id, college_code (机构编码), parent_org_code (父机构编码)