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  • Java常用算法

    (0)回调

    01.定义回调接口和事件

    02.实现回调接口

    03.在运行类传入回调接口

    04.调起类传入 实现的回调接口对象

    1.冒泡排序

    原理:依次递归,两两交换

        int[] ss=new int[]{11,43,45,12,34,45,13,99,9,1};
            for (int i = 0; i < ss.length; i++) {
                for (int j = 0; j <ss.length-1-i ; j++) {//第二次遍历无需涉及上次遍历过的最后位置
                    if(ss[j]>ss[j+1]){
                        int s=ss[j];//遍历两两交换
                        ss[j]=ss[j+1];
                        ss[j+1]=s;
                    }
                }            
            }

    2.快速排序

    原理:选取一个基值,把数小的放在基值左边,大的放在基值右边,如此后再分治递归

      if(i<j){  
                //通过一趟排序获得基值  
                int pivot = quickSort(array, i, j);  
                //分治递归  
                partation(array, i, pivot-1);  
                partation(array, pivot+1, j);  
            } 
    
      private static int quickSort(int[] array,int i, int j) {  
            //一般默认设置基值为首位的值  
            int pivot = array[i];  
              
            while(i<j) {  
                //当基值小于最后一位的值,则将j的值减1,得到第一个比基值小的值,然后覆盖  
                while(i<j&&array[j]>pivot) {  
                    j--;  
                }  
                array[i] = array[j];  
       
                //当基值大于第一位的值,则将i的值加1,得到第一个比基值大的值,然后覆盖  
                while(i<j&&array[i]<pivot) {  
                    i++;  
                }  
                array[j] = array[i];  
            }  
    
            array[i] = pivot;  // 位置换成基值,左边比基值小,右边比基值大
             
            return i;  
        }  

    3.二分法

    原理:每次从最大数和最小数的中小开始往左右遍历,在遍历过程中不断缩小low和high

    public static int BinarySearch(int[] array, int T)
        {
            int low, high, mid;
            low = 0;
            high = array.length - 1;
            while (low <= high)
            {
                mid = (low + high) / 2; //重新计算mid
                if (array[mid] < T)
                {
                    low = mid + 1;
                }
                else if (array[mid]>T)
                {
                    high = mid - 1;
                }
                else 
                {
                    return mid;
                }
            }
            return -1;
    }

    4.二叉树递归

    先序遍历:
    1 2 4 8 9 5 3 6 7
    中序遍历:
    8 4 9 2 5 1 6 3 7
    后序遍历:
    8 9 4 5 2 6 7 3 1

     /** 
         * 先序遍历 
         *  
         */  
        public static void preOrderTraverse(Node node) {  
            if (node == null)  
                return;  
            System.out.print(node.data + " ");  
            preOrderTraverse(node.leftChild);  
            preOrderTraverse(node.rightChild);  
        }  
      
        /** 
         * 中序遍历 
         *  
         */  
        public static void inOrderTraverse(Node node) {  
            if (node == null)  
                return;  
            inOrderTraverse(node.leftChild);  
            System.out.print(node.data + " ");  
            inOrderTraverse(node.rightChild);  
        }  
      
        /** 
         * 后序遍历 
         *  
         */  
        public static void postOrderTraverse(Node node) {  
            if (node == null)  
                return;  
            postOrderTraverse(node.leftChild);  
            postOrderTraverse(node.rightChild);  
            System.out.print(node.data + " ");  
        }  
        

    5.二叉树非递归

     // 先序遍历非递归     
        public static void preOrder2(BinTree t) {    
            Stack<BinTree> s = new Stack<BinTree>();    
            while (t != null || !s.empty()) {    
                while (t != null) {    
                    System.out.print(t.date);    
                    s.push(t);    //入栈
                    t = t.lchild;    
                }    
                if (!s.empty()) {    
                    t = s.pop();    //获取出栈元素后出栈
                    t = t.rchild;    
                }    
            }    
        }    
        
        // 中序遍历非递归     
        public static void InOrder2(BinTree t) {    
            Stack<BinTree> s = new Stack<BinTree>();    
            while (t != null || !s.empty()) {    
                while (t != null) {    
                    s.push(t);    
                    t = t.lchild;    
                }    
                if (!s.empty()) {    
                    t = s.pop();    
                    System.out.print(t.date);    
                    t = t.rchild;    
                }    
            }    
        }    
        
        // 后序遍历非递归     
        public static void PostOrder2(BinTree t) {    
            Stack<BinTree> s = new Stack<BinTree>();    
            Stack<Integer> s2 = new Stack<Integer>();    
            Integer i = new Integer(1);    
            while (t != null || !s.empty()) {    
                while (t != null) {    
                    s.push(t);    
                    s2.push(new Integer(0));    
                    t = t.lchild;    
                }    
                while (!s.empty() && s2.peek().equals(i)) {    
                    s2.pop();    
                    System.out.print(s.pop().date);    
                }    
        
                if (!s.empty()) {    
                    s2.pop();    
                    s2.push(new Integer(1));    
                    t = s.peek();    
                    t = t.rchild;    
                }    
            }    
        }    

    302

        public String firstRequest(String url) throws IOException {
                System.out.println("访问地址:" + url);
                URL serverUrl = new URL(url);
                HttpURLConnection conn = (HttpURLConnection) serverUrl
                        .openConnection();
    
                conn.setRequestMethod("GET");
    
                // 必须设置false,否则会自动redirect到Location的地址
                conn.setInstanceFollowRedirects(false);
    
                conn.addRequestProperty("Accept-Charset", "UTF-8;");
                conn.addRequestProperty("User-Agent",
                        "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:49.0) Gecko/20100101 Firefox/49.0");
                conn.addRequestProperty("Referer", "http://jenkins.rnd.meizu.com/login?from=%2F");
                conn.connect();
    
                System.out.println(conn.getHeaderField(7));//根据返回header中key组数,获取登录cookie
                String[] cookies = conn.getHeaderField(7).split("\;");
                String cookie = cookies[0];
    
    
                String location = conn.getHeaderField("Location");
                serverUrl = new URL(location);
                conn = (HttpURLConnection) serverUrl.openConnection();
                conn.setRequestMethod("GET");
                conn.addRequestProperty("Accept-Charset", "UTF-8;");
                conn.addRequestProperty("User-Agent",
                        "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:49.0) Gecko/20100101 Firefox/49.0");
                conn.addRequestProperty("Referer", "http://jenkins.rnd.meizu.com/login?from=%2F");
                conn.connect();
                System.out.println("跳转地址:" + location);
    
                return (cookie);
    
            }
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  • 原文地址:https://www.cnblogs.com/season-xie/p/6506310.html
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