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  • 【leetcode】1207. Unique Number of Occurrences

    题目如下:

    Given an array of integers arr, write a function that returns true if and only if the number of occurrences of each value in the array is unique.

    Example 1:

    Input: arr = [1,2,2,1,1,3]
    Output: true
    Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences.

    Example 2:

    Input: arr = [1,2]
    Output: false
    

    Example 3:

    Input: arr = [-3,0,1,-3,1,1,1,-3,10,0]
    Output: true

    Constraints:

    • 1 <= arr.length <= 1000
    • -1000 <= arr[i] <= 1000

    解题思路:很简单的题目。

    代码如下:

    class Solution(object):
        def uniqueOccurrences(self, arr):
            """
            :type arr: List[int]
            :rtype: bool
            """
            dic = {}
            for i in arr:
                dic[i] = dic.setdefault(i,0) + 1
            dic_exist = {}
            for v in dic.itervalues():
                if v in dic_exist:
                    return False
                dic_exist[v] = 1
            return True
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  • 原文地址:https://www.cnblogs.com/seyjs/p/11616700.html
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