【leetcode】1374. Generate a String With Characters That Have Odd Counts

题目如下：

Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times.

The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.  

Example 1:

Input: n = 4
Output: "pppz"
Explanation: "pppz" is a valid string since the character 'p' occurs three times and the character 'z' occurs once. Note that there are many other valid strings such as "ohhh" and "love".

Example 2:

Input: n = 2
Output: "xy"
Explanation: "xy" is a valid string since the characters 'x' and 'y' occur once. Note that there are many other valid strings such as "ag" and "ur".

Example 3:

Input: n = 7
Output: "holasss"

Constraints:

• 1 <= n <= 500

解题思路：非常简单了。如果n是偶数，那就n-1个a 和1个b；如果n是奇数，则n个a。

代码如下：

class Solution(object):
    def generateTheString(self, n):
        """
        :type n: int
        :rtype: str
        """
        return 'a' * n if n % 2 == 1 else 'a' * (n-1) + 'b'