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  • 【leetcode】1399. Count Largest Group

    题目如下:

    Given an integer n. Each number from 1 to n is grouped according to the sum of its digits. 

    Return how many groups have the largest size. 

    Example 1:

    Input: n = 13
    Output: 4
    Explanation: There are 9 groups in total, they are grouped according sum of its digits of numbers from 1 to 13:
    [1,10], [2,11], [3,12], [4,13], [5], [6], [7], [8], [9]. There are 4 groups with largest size.
    

    Example 2:

    Input: n = 2
    Output: 2
    Explanation: There are 2 groups [1], [2] of size 1.
    

    Example 3:

    Input: n = 15
    Output: 6
    

    Example 4:

    Input: n = 24
    Output: 5

    Constraints:

    • 1 <= n <= 10^4

    解题思路:把一个数字的位和算出来就行了。

    代码如下:

    class Solution(object):
        def countLargestGroup(self, n):
            """
            :type n: int
            :rtype: int
            """
            dic = {}
            max_count = 0
            for i in range(1,n+1):
                count = 0
                while i > 0:
                    count += i%10
                    i/=10
                dic[count] = dic.setdefault(count,0)+1
                max_count = max(dic[count],max_count)
            res = 0
            for value in dic.itervalues():
                if value == max_count:res += 1
    
            return res
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  • 原文地址:https://www.cnblogs.com/seyjs/p/12771498.html
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