zoukankan      html  css  js  c++  java
  • 【leetcode】1455. Check If a Word Occurs As a Prefix of Any Word in a Sentence

    题目如下:

    Given a sentence that consists of some words separated by a single space, and a searchWord.

    You have to check if searchWord is a prefix of any word in sentence.

    Return the index of the word in sentence where searchWord is a prefix of this word (1-indexed).

    If searchWord is a prefix of more than one word, return the index of the first word (minimum index). If there is no such word return -1.

    A prefix of a string S is any leading contiguous substring of S.

    Example 1:

    Input: sentence = "i love eating burger", searchWord = "burg"
    Output: 4
    Explanation: "burg" is prefix of "burger" which is the 4th word in the sentence.
    

    Example 2:

    Input: sentence = "this problem is an easy problem", searchWord = "pro"
    Output: 2
    Explanation: "pro" is prefix of "problem" which is the 2nd and the 6th word in the sentence, but we return 2 as it's the minimal index.
    

    Example 3:

    Input: sentence = "i am tired", searchWord = "you"
    Output: -1
    Explanation: "you" is not a prefix of any word in the sentence.
    

    Example 4:

    Input: sentence = "i use triple pillow", searchWord = "pill"
    Output: 4
    

    Example 5:

    Input: sentence = "hello from the other side", searchWord = "they"
    Output: -1 

    Constraints:

    • 1 <= sentence.length <= 100
    • 1 <= searchWord.length <= 10
    • sentence consists of lowercase English letters and spaces.
    • searchWord consists of lowercase English letters.

    解题思路:很简单的题目,挨个比对就是了。

    代码如下:

    class Solution(object):
        def isPrefixOfWord(self, sentence, searchWord):
            """
            :type sentence: str
            :type searchWord: str
            :rtype: int
            """
            word_list = sentence.split(' ')
            for i in range(len(word_list)):
                if word_list[i].startswith(searchWord):
                    return i + 1
            return -1
  • 相关阅读:
    python操作 pdf 资料
    PyQt 实现 GUI
    https://zhuanlan.zhihu.com/p/60647332
    [转]框架《Python深度学习基于PyTorch》PDF+代码检测
    python学习资料
    Python虚拟环境打包
    A* 算法详解
    opencv python 图像二值化/简单阈值化/大津阈值法
    语音识别——基于深度学习的中文语音识别tutorial(代码实践)
    OpenCV资料
  • 原文地址:https://www.cnblogs.com/seyjs/p/13046897.html
Copyright © 2011-2022 走看看